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anonymous
 one year ago
Molly can prepare a report in 6 hours. Jere can prepare a report in only 4 hours.
Which of the following can be used to determine the amount of time it would take for Molly and Jere to prepare a report together?
anonymous
 one year ago
Molly can prepare a report in 6 hours. Jere can prepare a report in only 4 hours. Which of the following can be used to determine the amount of time it would take for Molly and Jere to prepare a report together?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 over 6 plus 1 over x equals 1 over 4 1 over x plus 1 over 4 equals 1 over 6 1 over 4 plus 1 over 6 equals x over 10 1 over 6 plus 1 over 4 equals 1 over x

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2Hint M = time it takes for molly to prepare the report (with no help from others) J = time it takes for Jere to prepare the report (with no help from others) \[\large \frac{1}{\text{Molly's Time}}+\frac{1}{\text{Jere's Time}} = \frac{1}{\text{Time if they work together}}\] \[\large \frac{1}{M}+\frac{1}{J} = \frac{1}{\text{Time if they work together}}\] I'll let you finish

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yay:) Can I ask another?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nathaniel can weld a railing in 75 minutes. Brenda can weld a railing 25 minutes faster. If they work together, how many minutes does it take them to weld the railing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.025 minutes 30 minutes 50 minutes 150 minutes

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2same idea, just different numbers

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2\[\Large \frac{1}{75} + \frac{1}{25} = \frac{1}{x}\] x = time in minutes it takes them to do the job together

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2oh wait, I have the wrong equation

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2`Nathaniel can weld a railing in 75 minutes. Brenda can weld a railing 25 minutes faster.` so Brenda takes 7525 = 50 minutes \[\Large \frac{1}{75} + \frac{1}{50} = \frac{1}{x}\] isolate x

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2what does 1/75 + 1/50 turn into?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2add them up like normal fractions

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2well LCD actually but yeah

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yayyy!!!! Thankyou!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2I'll help with one last one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It takes Harland 15 minutes to rake all leaves in the front yard. If Trudy scatters the leaves while Harland rakes, it takes him 20 minutes to rake the leaves. How many minutes does it take Trudy to scatter all the leaves?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05 minutes 12 minutes 45 minutes 60 minutes

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm thinking 60 minutes

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2what does 1/20 + 1/15 add up to?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait! NVM! I did 1/151/20 instead of addition

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04x/60x +3x/6x =60/60x

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2oh I have a typo, let me fix it

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2the 1/y should have been negative

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2sorry another typo, but I'm sure this time it's correct x = time it takes for Harland to rake all the leaves (without Trudy in the way) y = time it takes Trudy to scatter all the leaves (without Harland in the way) z = time it takes Harland to rake all the leaves with Trudy scattering the leaves at the same time \[\Large \frac{1}{x}  \frac{1}{y} = \frac{1}{z}\] \[\Large \frac{1}{15}  \frac{1}{y} = \frac{1}{20}\] \[\Large \frac{1}{15}  \frac{1}{y} + \frac{1}{y} = \frac{1}{20} + \frac{1}{y}\] \[\Large \frac{1}{15} = \frac{1}{20} + \frac{1}{y}\] \[\Large \frac{1}{15}  \frac{1}{20} = \frac{1}{20} + \frac{1}{y}  \frac{1}{20}\] \[\Large \frac{1}{15}  \frac{1}{20} = \frac{1}{y}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2not sure why I'm being so careless lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would the answer be 60?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2anyways, you had the right idea in saying 1/15  1/20 that leads to 1/60 so y = 60

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much for all your help:)))
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