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anonymous

  • one year ago

Molly can prepare a report in 6 hours. Jere can prepare a report in only 4 hours. Which of the following can be used to determine the amount of time it would take for Molly and Jere to prepare a report together?

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  1. anonymous
    • one year ago
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    1 over 6 plus 1 over x equals 1 over 4 1 over x plus 1 over 4 equals 1 over 6 1 over 4 plus 1 over 6 equals x over 10 1 over 6 plus 1 over 4 equals 1 over x

  2. jim_thompson5910
    • one year ago
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    Hint M = time it takes for molly to prepare the report (with no help from others) J = time it takes for Jere to prepare the report (with no help from others) \[\large \frac{1}{\text{Molly's Time}}+\frac{1}{\text{Jere's Time}} = \frac{1}{\text{Time if they work together}}\] \[\large \frac{1}{M}+\frac{1}{J} = \frac{1}{\text{Time if they work together}}\] I'll let you finish

  3. anonymous
    • one year ago
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    So would it be D?

  4. anonymous
    • one year ago
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    @jim_thompson5910

  5. jim_thompson5910
    • one year ago
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    correct

  6. anonymous
    • one year ago
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    Yay:) Can I ask another?

  7. jim_thompson5910
    • one year ago
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    sure

  8. anonymous
    • one year ago
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    Ok hold on please

  9. anonymous
    • one year ago
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    Nathaniel can weld a railing in 75 minutes. Brenda can weld a railing 25 minutes faster. If they work together, how many minutes does it take them to weld the railing?

  10. anonymous
    • one year ago
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    25 minutes 30 minutes 50 minutes 150 minutes

  11. jim_thompson5910
    • one year ago
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    same idea, just different numbers

  12. jim_thompson5910
    • one year ago
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    \[\Large \frac{1}{75} + \frac{1}{25} = \frac{1}{x}\] x = time in minutes it takes them to do the job together

  13. anonymous
    • one year ago
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    sO 50 minutes ?

  14. jim_thompson5910
    • one year ago
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    oh wait, I have the wrong equation

  15. anonymous
    • one year ago
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    ok:)

  16. jim_thompson5910
    • one year ago
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    `Nathaniel can weld a railing in 75 minutes. Brenda can weld a railing 25 minutes faster.` so Brenda takes 75-25 = 50 minutes \[\Large \frac{1}{75} + \frac{1}{50} = \frac{1}{x}\] isolate x

  17. anonymous
    • one year ago
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    how do I do that?

  18. jim_thompson5910
    • one year ago
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    what does 1/75 + 1/50 turn into?

  19. jim_thompson5910
    • one year ago
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    add them up like normal fractions

  20. anonymous
    • one year ago
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    150 is the gcf

  21. jim_thompson5910
    • one year ago
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    yes

  22. jim_thompson5910
    • one year ago
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    well LCD actually but yeah

  23. anonymous
    • one year ago
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    2x+3x/150x=150/150x

  24. anonymous
    • one year ago
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    So 30 min?

  25. jim_thompson5910
    • one year ago
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    yes x = 30

  26. anonymous
    • one year ago
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    Yayyy!!!! Thank-you!

  27. anonymous
    • one year ago
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    Up for another?

  28. jim_thompson5910
    • one year ago
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    I'll help with one last one

  29. anonymous
    • one year ago
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    It takes Harland 15 minutes to rake all leaves in the front yard. If Trudy scatters the leaves while Harland rakes, it takes him 20 minutes to rake the leaves. How many minutes does it take Trudy to scatter all the leaves?

  30. anonymous
    • one year ago
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    Deal:)

  31. anonymous
    • one year ago
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    5 minutes 12 minutes 45 minutes 60 minutes

  32. anonymous
    • one year ago
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    I'm thinking 60 minutes

  33. jim_thompson5910
    • one year ago
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    what does 1/20 + 1/15 add up to?

  34. anonymous
    • one year ago
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    Wait! NVM! I did 1/15-1/20 instead of addition

  35. anonymous
    • one year ago
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    Um the LCD is 60

  36. anonymous
    • one year ago
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    4x/60x +3x/6x =60/60x

  37. jim_thompson5910
    • one year ago
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    oh I have a typo, let me fix it

  38. anonymous
    • one year ago
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    kk

  39. jim_thompson5910
    • one year ago
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    the 1/y should have been negative

  40. anonymous
    • one year ago
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    Ok :)

  41. jim_thompson5910
    • one year ago
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    sorry another typo, but I'm sure this time it's correct x = time it takes for Harland to rake all the leaves (without Trudy in the way) y = time it takes Trudy to scatter all the leaves (without Harland in the way) z = time it takes Harland to rake all the leaves with Trudy scattering the leaves at the same time \[\Large \frac{1}{x} - \frac{1}{y} = \frac{1}{z}\] \[\Large \frac{1}{15} - \frac{1}{y} = \frac{1}{20}\] \[\Large \frac{1}{15} - \frac{1}{y} + \frac{1}{y} = \frac{1}{20} + \frac{1}{y}\] \[\Large \frac{1}{15} = \frac{1}{20} + \frac{1}{y}\] \[\Large \frac{1}{15} - \frac{1}{20} = \frac{1}{20} + \frac{1}{y} - \frac{1}{20}\] \[\Large \frac{1}{15} - \frac{1}{20} = \frac{1}{y}\]

  42. jim_thompson5910
    • one year ago
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    not sure why I'm being so careless lol

  43. anonymous
    • one year ago
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    so would the answer be 60?

  44. anonymous
    • one year ago
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    It's fine<3

  45. jim_thompson5910
    • one year ago
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    anyways, you had the right idea in saying 1/15 - 1/20 that leads to 1/60 so y = 60

  46. anonymous
    • one year ago
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    Thanks so much for all your help:)))

  47. jim_thompson5910
    • one year ago
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    no problem

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