anonymous
  • anonymous
Quadrilateral LMNO has diagonals that intersect at point P. If LP = 6x – 5, MP = y + 25, NP = 4x + 17, and OP = 5y + 29, find the values of x and y such that LMNO is a parallelogram. A. x = 11, y = 1 B. x = 10, y = –1 C. x = 11, y = –1 D. x = –1, y = 11
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
Remember, parallelogram's diagonals split each other in half
anonymous
  • anonymous
soo..

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anonymous
  • anonymous
i am still confused
anonymous
  • anonymous
In wordy terms, they bisect each other
anonymous
  • anonymous
So LP = PN and MP = PO
anonymous
  • anonymous
It's quite simple, you just have to know the properties
anonymous
  • anonymous
i still dont get how to find x and y
anonymous
  • anonymous
okay so it isnt A
anonymous
  • anonymous
I told you. Look at the picture. The diagonals of a parallelogram bisect each other. This means LP = PN and MP = PO. What is so hard about that. You have what they say LP, PN, MP, and PO are, so plug their values in.
anonymous
  • anonymous
Just a side note, PN and NP are exactly the same thing
anonymous
  • anonymous
Did you get your answer yet?
anonymous
  • anonymous
im thinking B because the Y are the same
anonymous
  • anonymous
? Y are the same? what are you talking about
anonymous
  • anonymous
the y value is -1
anonymous
  • anonymous
for OP and MP the answer is -1 and equals 24 for both
anonymous
  • anonymous
but i dont get the LP and NP
anonymous
  • anonymous
Jesus christ -_- LP = 6x – 5, MP = y + 25, NP = 4x + 17, and OP = 5y + 29 And the diagonals of a parallelogram bisect each other. This means LP = NP and MP = OP. So; 6x-5 = 4x+17 and y + 25 = 5y + 29
anonymous
  • anonymous
Did you take algebra 1???
anonymous
  • anonymous
no i took buisness math because it was a hell of a lot easier.
anonymous
  • anonymous
then how are taking geometry, you can't unless you take algebra 1
anonymous
  • anonymous
they by passed me lol
anonymous
  • anonymous
ok i dont get 6x-5 = 4x+17 because neither 11 or 10 works
anonymous
  • anonymous
oh wait ITS 11!!
anonymous
  • anonymous
ok i understand that part
anonymous
  • anonymous
ok the answer is C thank u
anonymous
  • anonymous
OMG here's what you gotta do. Call whatever class you're taking Cancel it Sign up for Algebra 1. Finish algebra 1. Come back and then take geometry. Because you can't keep on just doing guess and check or plugging in x for y. It just doesn't work when you get to the harder problems.
anonymous
  • anonymous
I'll draw out the correct way to do it.
anonymous
  • anonymous
I take geometry online. Im finished with highschool. I cant just cancel a class.
anonymous
  • anonymous
LP = 6x – 5, MP = y + 25, NP = 4x + 17, and OP = 5y + 29 And the diagonals of a parallelogram bisect each other. This means LP = NP and MP = OP. So; 6x-5 = 4x+17 and y + 25 = 5y + 29 |dw:1436840739993:dw|
anonymous
  • anonymous
Ah that makes it easier. So i would suggest you to take algebra 1 consecutively with geometry, which will make life a lot easier.
anonymous
  • anonymous
The lazy way out never works out, trust me on that
anonymous
  • anonymous
Dang i sound like a mom right now
anonymous
  • anonymous
lmao i cant take anymore classes geometry is the only one i need im just worrying about finishing this geometry course before august so i never have to take math again
anonymous
  • anonymous
i already took algebra 1 i just got a really low grade but i still passed, and that was 4 years ago
anonymous
  • anonymous
Thats gonna be a truckload, since it seems you can't isolate variables and etc. I would suggest u check this out http://www.purplemath.com/modules/solvelin.htm
anonymous
  • anonymous
You at least need to know how to isolate variables for geometry, because plugging in stuff takes a truckload of time
anonymous
  • anonymous
na im 50% ahead of the program. most answers are online lmao

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