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calculusxy

  • one year ago

How would I graph 2x + 3y = 6

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  1. calculusxy
    • one year ago
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    @jim_thompson5910

  2. calculusxy
    • one year ago
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    @satellite73

  3. jim_thompson5910
    • one year ago
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    if x = 0, then what is the value of y?

  4. calculusxy
    • one year ago
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    0 + 3y = 6 y = 2

  5. jim_thompson5910
    • one year ago
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    so (0,2) is one point on the graph

  6. jim_thompson5910
    • one year ago
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    if y = 0, then x = ??

  7. calculusxy
    • one year ago
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    x = 3

  8. jim_thompson5910
    • one year ago
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    (3,0) is the second point you need just 2 points to graph a linear equation

  9. calculusxy
    • one year ago
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    I mean I need help using it "algebraically"

  10. jim_thompson5910
    • one year ago
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    you mean solving 2x + 3y = 6 for y?

  11. calculusxy
    • one year ago
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    2x + 3y = 6 2x - 2x + 3y = 6 - 2x 3y = 6 - 2x

  12. calculusxy
    • one year ago
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    But I am having confusions solving it from there.

  13. jim_thompson5910
    • one year ago
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    to isolate y in 3y = 6-2x, divide both sides by 3

  14. calculusxy
    • one year ago
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    So it would be y = 2 - 2/3x ?

  15. jim_thompson5910
    • one year ago
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    yes \[\Large y = -\frac{2}{3}x + 2\]

  16. calculusxy
    • one year ago
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    Why did you switch it ?

  17. calculusxy
    • one year ago
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    Like is it necessary to do that?

  18. jim_thompson5910
    • one year ago
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    I placed it into y = mx+b form

  19. jim_thompson5910
    • one year ago
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    no it's not mandatory

  20. calculusxy
    • one year ago
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    Okay thanks :)

  21. jim_thompson5910
    • one year ago
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    np

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