anonymous
  • anonymous
A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? ~h(t) = at2 + vt + h0 A.0.05 s B.2.03 s C.3.80 s D.3.70 s
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
they don't give you much to work with here do they?
anonymous
  • anonymous
your actual job is to solve \[-16t^2+60t+3=0\] that is all
jim_thompson5910
  • jim_thompson5910
saying `acceleration due to gravity is –16 ft/s2` is false the acceleration due to gravity is actually 32 ft/s^2

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jim_thompson5910
  • jim_thompson5910
but the equation -16t^2 + 60t + 3 = 0 is correct
anonymous
  • anonymous
thank you guys a lot!

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