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anonymous
 one year ago
A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground?
~h(t) = at2 + vt + h0
A.0.05 s
B.2.03 s
C.3.80 s
D.3.70 s
anonymous
 one year ago
A toy rocket is launched straight up into the air with an initial velocity of 60 ft/s from a table 3 ft above the ground. If acceleration due to gravity is –16 ft/s2, approximately how many seconds after the launch will the toy rocket reach the ground? ~h(t) = at2 + vt + h0 A.0.05 s B.2.03 s C.3.80 s D.3.70 s

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they don't give you much to work with here do they?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your actual job is to solve \[16t^2+60t+3=0\] that is all

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0saying `acceleration due to gravity is –16 ft/s2` is false the acceleration due to gravity is actually 32 ft/s^2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0but the equation 16t^2 + 60t + 3 = 0 is correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you guys a lot!
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