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anonymous

  • one year ago

Please help! Picture included.

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  1. anonymous
    • one year ago
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  2. misty1212
    • one year ago
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    HI!!

  3. misty1212
    • one year ago
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    the function changes at \(x=1\) right?

  4. anonymous
    • one year ago
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    I have no idea :/ I'm really confused with what the questions are asking for Part 2 especially

  5. misty1212
    • one year ago
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    erase the line to the left of \(x=1\) and erase the parabola to the right of \(x=1\)

  6. anonymous
    • one year ago
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    Wait so just the entire left side?

  7. misty1212
    • one year ago
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    your function is two different things right? one part is a parabola, the other is a line

  8. misty1212
    • one year ago
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    it changes at 1

  9. misty1212
    • one year ago
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    to the left of 1 it is a parabola to the right of 1 it is a line

  10. misty1212
    • one year ago
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    here is a nice picture http://www.wolframalpha.com/widgets/view.jsp?id=5075763dba6ec763f31004272f8aa7fa

  11. misty1212
    • one year ago
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    ok that didn't work, but you can fill it in for yourself to see what it should look like i can't send it with fields filled out

  12. anonymous
    • one year ago
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    wait let me take a picture with the erased parts bc i'm not sure if i erased it correctly

  13. anonymous
    • one year ago
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    @misty1212

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  14. misty1212
    • one year ago
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    yeah good job!

  15. anonymous
    • one year ago
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    yayy that's c right? how would i do d

  16. misty1212
    • one year ago
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    closed circle goes on the parabola, because of the \(x\leq 1\) open circle on the line because of \(x>1\)

  17. misty1212
    • one year ago
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    get rid of the arrows

  18. anonymous
    • one year ago
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    do i put circles at the end of each line and parabola

  19. anonymous
    • one year ago
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    oh okay thank you! :)

  20. misty1212
    • one year ago
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    |dw:1436842571269:dw|

  21. anonymous
    • one year ago
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    i don't put it on the other side?

  22. misty1212
    • one year ago
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    nope

  23. misty1212
    • one year ago
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    just at the break

  24. anonymous
    • one year ago
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    okay thank you so much!!

  25. misty1212
    • one year ago
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    \[\color\magenta\heartsuit\]

  26. UsukiDoll
    • one year ago
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    I'm going to add some information. So basically, we were given a piecewise function \[x^2, x \leq 1 \] this means that when our x is less than or equal to 1 we have to graph \[x^2 \] since we we have \[\leq \] we draw a closed circle. This also applies when we have \[\geq \] ( we draw a closed circle) \[2x+1, x > 1\] this means that our x is greater than 1. So on the graph, we draw 2x+1 after x = 1 since we have > we draw an open circle. This also applies when we have < (we draw an open circle. So our graph will look at this |dw:1436843159513:dw|

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is replying to Can someone tell me what button the professor is hitting...

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