anonymous
  • anonymous
Please help! Picture included.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
the function changes at \(x=1\) right?

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More answers

anonymous
  • anonymous
I have no idea :/ I'm really confused with what the questions are asking for Part 2 especially
misty1212
  • misty1212
erase the line to the left of \(x=1\) and erase the parabola to the right of \(x=1\)
anonymous
  • anonymous
Wait so just the entire left side?
misty1212
  • misty1212
your function is two different things right? one part is a parabola, the other is a line
misty1212
  • misty1212
it changes at 1
misty1212
  • misty1212
to the left of 1 it is a parabola to the right of 1 it is a line
misty1212
  • misty1212
here is a nice picture http://www.wolframalpha.com/widgets/view.jsp?id=5075763dba6ec763f31004272f8aa7fa
misty1212
  • misty1212
ok that didn't work, but you can fill it in for yourself to see what it should look like i can't send it with fields filled out
anonymous
  • anonymous
wait let me take a picture with the erased parts bc i'm not sure if i erased it correctly
anonymous
  • anonymous
@misty1212
1 Attachment
misty1212
  • misty1212
yeah good job!
anonymous
  • anonymous
yayy that's c right? how would i do d
misty1212
  • misty1212
closed circle goes on the parabola, because of the \(x\leq 1\) open circle on the line because of \(x>1\)
misty1212
  • misty1212
get rid of the arrows
anonymous
  • anonymous
do i put circles at the end of each line and parabola
anonymous
  • anonymous
oh okay thank you! :)
misty1212
  • misty1212
|dw:1436842571269:dw|
anonymous
  • anonymous
i don't put it on the other side?
misty1212
  • misty1212
nope
misty1212
  • misty1212
just at the break
anonymous
  • anonymous
okay thank you so much!!
misty1212
  • misty1212
\[\color\magenta\heartsuit\]
UsukiDoll
  • UsukiDoll
I'm going to add some information. So basically, we were given a piecewise function \[x^2, x \leq 1 \] this means that when our x is less than or equal to 1 we have to graph \[x^2 \] since we we have \[\leq \] we draw a closed circle. This also applies when we have \[\geq \] ( we draw a closed circle) \[2x+1, x > 1\] this means that our x is greater than 1. So on the graph, we draw 2x+1 after x = 1 since we have > we draw an open circle. This also applies when we have < (we draw an open circle. So our graph will look at this |dw:1436843159513:dw|

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