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anonymous
 one year ago
Is the equation P = 500(1.03)n a model of growth or exponential decay?
anonymous
 one year ago
Is the equation P = 500(1.03)n a model of growth or exponential decay?

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dan815
 one year ago
Best ResponseYou've already chosen the best response.0P = 500(1.03)^n make sure u add that exponent sigh

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1\(\large k^n\) increases as n increases for \( k> 1\) \(\large k^n \) decreases as n increases for \(0 \lt k \lt 1\) In your case, you have k = 1.03, which is greater than 1, so this function is growth.
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