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anonymous

  • one year ago

According to the general equation for conditional probability, if P(A∩B)=3/7 and P(B)=7/8 , what is P(A|B) ?

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  1. butterflydreamer
    • one year ago
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    http://prntscr.com/7sfwan <- this is your general equation

  2. anonymous
    • one year ago
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    hmmmm

  3. kropot72
    • one year ago
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    The formula needed is \[\large P(A|B)=\frac{P(A\cap B)}{P(B)}\]

  4. butterflydreamer
    • one year ago
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    |dw:1436849165374:dw|

  5. anonymous
    • one year ago
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    A. 40/49 B. 32/49 C. 16/49 D. 24/49

  6. anonymous
    • one year ago
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    looking for help dont have to tell the answer if you dont feel like it

  7. anonymous
    • one year ago
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    i really want to understand this complicated stuff

  8. butterflydreamer
    • one year ago
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    So all you need to do is simplify the fraction :) \[\frac{ 3 }{ 7 } \div \frac{ 7 }{ 8 } = \frac{ 3 }{ 7 } \times \frac{ 8 }{ 7 } = ? \]

  9. butterflydreamer
    • one year ago
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    you just substitute the values that is given (in the question) into the general formula (above) and then you work it out normally ^_^

  10. anonymous
    • one year ago
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    me = mind blown

  11. anonymous
    • one year ago
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    i dont understand sorry

  12. UsukiDoll
    • one year ago
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    we are given P(A∩B)=3/7 and P(B)=7/8 so we need to find out P(A|B) which there's a formula for that \(\color{blue}{\text{Originally Posted by}}\) @kropot72 The formula needed is \[\large P(A|B)=\frac{P(A\cap B)}{P(B)}\] \(\color{blue}{\text{End of Quote}}\)

  13. anonymous
    • one year ago
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    ohh its 24/49

  14. anonymous
    • one year ago
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    lol i was confused at first

  15. butterflydreamer
    • one year ago
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    we are given: \[ P(A∩B)=3/7 \] and \[P(B)=7/8\] We want to find : \[P(A|B) =?\] To do this, we need to use the general formula for conditional probability: \[P(A|B)=\frac{ P(A∩B) }{ P(B) } \]

  16. UsukiDoll
    • one year ago
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    @butterflydreamer he got the answer already and it is 24/49

  17. butterflydreamer
    • one year ago
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    computer lagged xD but yass

  18. anonymous
    • one year ago
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    thanks guys :)

  19. butterflydreamer
    • one year ago
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    no problem :)

  20. anonymous
    • one year ago
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    i fanned ya :)

  21. butterflydreamer
    • one year ago
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    *thanks :)!

  22. anonymous
    • one year ago
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    :)

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