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anonymous
 one year ago
Need Help, medal + fan:
Which are true of the function f(x) = 49 (1/7)x? Check all that apply.
A:The domain is the set of all real numbers.
B:The range is the set of all real numbers.
C:The domain is x > 0.
D:The range is y > 0.
E:As x increases by 1, each yvalue is oneseventh of the previous yvalue.
F:The initial value for the function is
anonymous
 one year ago
Need Help, medal + fan: Which are true of the function f(x) = 49 (1/7)x? Check all that apply. A:The domain is the set of all real numbers. B:The range is the set of all real numbers. C:The domain is x > 0. D:The range is y > 0. E:As x increases by 1, each yvalue is oneseventh of the previous yvalue. F:The initial value for the function is

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\large f(x)=49(\frac{1}{7})^x \] is this the function for the question? or \[\large f(x)=49(\frac{1}{7})x \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ok... well our function doesn't have denominators so there are no restrictions.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2the domain is at the xaxis the range is at the yaxis

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we need to graph this function tt

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.0note: you can also rewrite your function as: dw:1436850224394:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we need x = 1,2,3... and so on.. for \[\large f(x)=49(\frac{1}{7})^x \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2we can use desmos. easier XD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh okay you have to graph to see it..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wasn't graphing it, so that is why it was really difficult to see

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yeah... sometimes questions are easier when you graph but since this function is too screwed up (I don't feel like doing it manually lol) we use desmos which graphs it for us

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So from the graph, I already concluded what some of the answers could be, but still not sure if I am right, could you check to see? I will screenshot it

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2The first 2 is indeed all real numbers as I mentioned earlier we don't have a function that's like a fraction ex. \[f(x) =\frac{1}{x2} \] which means we can't have x be 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, so A and B are correct..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2yes... hmm interesting on the last one.. I mean that would work if x = 1, but I could've sworn that initial value would mean that x = 0 .

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2like.. if x = 1 \[\large f(1)=49(\frac{1}{7})^1\] \[\large f(1)=49(\frac{1}{7})\] \[\large f(1)=(\frac{49}{7})=7\] If x = 0 \[\large f(0)=49(\frac{1}{7})^0\] (due to the zero exponent rule.. anything to the 0 results in 1 ) \[\large f(0)=49(1) = 49\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, we are getting somewhere haha. So we already know A and B are correct, anything else I am missing, or something I marked incorrectly?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\large f(2)=49(\frac{1}{7})^2\] \[\large f(2)=49(\frac{1}{49})\] \[\large f(2)=1\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2when my x is increasing I have f(0) = 49 f(1) = 7 f(2) = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So Y is decreasing..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I'm confused at that wording though... for the second to the last .. but yeah my y is going down.. fast.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2and it claims that when x is increasing the previous y is 1/7 th of the previous y value.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right...? That is not true though. so we can eliminate that one

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I don't think so it's like 49 ./ 7 =7 7/7 = 1 Then again maybe if I calculate f(3) \[\large f(3)=49(\frac{1}{7})^3 \] \[\large f(3)=(\frac{49}{343}) \] \[\large f(3)=(\frac{1}{7}) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2let's try f(4) maybe that question is talking about that? \[\large f(4)=49(\frac{1}{7})^4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey I'm sorry I am running really short on time, So lets just sum it up. What do you think are the answers?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\large f(4)=\frac{49}{2401}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[f(4) = \frac{1}{49}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2first two are fine last one is when x = 0 , so it's not 7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, and that is all?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ugh trying to think to those 3 ...

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2second to the last one is confusing... x.x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We'll just say no to that one...SO now we are left with C and D.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2if it's all reals then that would have the domain and range at >0

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I see it well on the range though. when y > 0

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2but the domain is smoosh... like it's just on the line

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so first two are fine domain is smoosh it's just 0 flat range is greater than 0 no idea  split on that one it's not 7 because x = 0 for initial conditions.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I think after x = 3 the previous is 1/7 due to 1/7 (1/7)(1/7) (1/7)(1/7)(1/7)
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