## anonymous one year ago Please help :) Describe the nature of the roots for this equation. 3x^2+x-5=0 A. Two complex roots B. Two real, rational roots C. One real, double root D. Two real, irrational roots

1. anonymous

well first we must find its roots. Do you know how?

2. anonymous

nope :/

3. anonymous

No idea?

4. anonymous

idk i think the first step is the quadratic formula?

5. anonymous

Yeah sure lets do the quadratic equation have you tried the problem already?

6. anonymous

not yet

7. anonymous

$-b+or - \sqrt{b ^{2}- 4ac} / 2a$

8. anonymous

-1+-$-1+- \sqrt{1 - 4(3) (-5)} / 6$

9. anonymous

the entire thing is divided by 6 right??

10. anonymous

-1+-|dw:1436851541331:dw|

11. anonymous

alright now what?

12. anonymous

so the sqrt of 61 has no factors it is an irrational root

13. anonymous

14. anonymous

is it d?

15. anonymous

Yes it is

16. anonymous

thank you!! what if it's 2x^2-x+1? I got -1+-(Sqrt -9)/4

17. anonymous

sqrt -9 = 3i that is a non real number

18. anonymous

-1+-(Sqrt -9)/4

19. anonymous

so would it be two complex numbers?

20. anonymous

complex roots*

21. anonymous

yes it is real numbers + or - an imaginary number are complex numbers

22. anonymous

in this case they are complex roots

23. anonymous

okay thanks so much! :)