anonymous
  • anonymous
Please help :) Describe the nature of the roots for this equation. 3x^2+x-5=0 A. Two complex roots B. Two real, rational roots C. One real, double root D. Two real, irrational roots
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
well first we must find its roots. Do you know how?
anonymous
  • anonymous
nope :/
anonymous
  • anonymous
No idea?

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anonymous
  • anonymous
idk i think the first step is the quadratic formula?
anonymous
  • anonymous
Yeah sure lets do the quadratic equation have you tried the problem already?
anonymous
  • anonymous
not yet
anonymous
  • anonymous
\[-b+or - \sqrt{b ^{2}- 4ac} / 2a\]
anonymous
  • anonymous
-1+-\[-1+- \sqrt{1 - 4(3) (-5)} / 6\]
anonymous
  • anonymous
the entire thing is divided by 6 right??
anonymous
  • anonymous
-1+-|dw:1436851541331:dw|
anonymous
  • anonymous
alright now what?
anonymous
  • anonymous
so the sqrt of 61 has no factors it is an irrational root
anonymous
  • anonymous
can you answer your question now?
anonymous
  • anonymous
is it d?
anonymous
  • anonymous
Yes it is
anonymous
  • anonymous
thank you!! what if it's 2x^2-x+1? I got -1+-(Sqrt -9)/4
anonymous
  • anonymous
sqrt -9 = 3i that is a non real number
anonymous
  • anonymous
-1+-(Sqrt -9)/4
anonymous
  • anonymous
so would it be two complex numbers?
anonymous
  • anonymous
complex roots*
anonymous
  • anonymous
yes it is real numbers + or - an imaginary number are complex numbers
anonymous
  • anonymous
in this case they are complex roots
anonymous
  • anonymous
okay thanks so much! :)

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