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anonymous

  • one year ago

Please help :) Describe the nature of the roots for this equation. 3x^2+x-5=0 A. Two complex roots B. Two real, rational roots C. One real, double root D. Two real, irrational roots

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  1. anonymous
    • one year ago
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    well first we must find its roots. Do you know how?

  2. anonymous
    • one year ago
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    nope :/

  3. anonymous
    • one year ago
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    No idea?

  4. anonymous
    • one year ago
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    idk i think the first step is the quadratic formula?

  5. anonymous
    • one year ago
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    Yeah sure lets do the quadratic equation have you tried the problem already?

  6. anonymous
    • one year ago
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    not yet

  7. anonymous
    • one year ago
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    \[-b+or - \sqrt{b ^{2}- 4ac} / 2a\]

  8. anonymous
    • one year ago
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    -1+-\[-1+- \sqrt{1 - 4(3) (-5)} / 6\]

  9. anonymous
    • one year ago
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    the entire thing is divided by 6 right??

  10. anonymous
    • one year ago
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    -1+-|dw:1436851541331:dw|

  11. anonymous
    • one year ago
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    alright now what?

  12. anonymous
    • one year ago
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    so the sqrt of 61 has no factors it is an irrational root

  13. anonymous
    • one year ago
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    can you answer your question now?

  14. anonymous
    • one year ago
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    is it d?

  15. anonymous
    • one year ago
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    Yes it is

  16. anonymous
    • one year ago
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    thank you!! what if it's 2x^2-x+1? I got -1+-(Sqrt -9)/4

  17. anonymous
    • one year ago
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    sqrt -9 = 3i that is a non real number

  18. anonymous
    • one year ago
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    -1+-(Sqrt -9)/4

  19. anonymous
    • one year ago
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    so would it be two complex numbers?

  20. anonymous
    • one year ago
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    complex roots*

  21. anonymous
    • one year ago
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    yes it is real numbers + or - an imaginary number are complex numbers

  22. anonymous
    • one year ago
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    in this case they are complex roots

  23. anonymous
    • one year ago
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    okay thanks so much! :)

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