## anonymous one year ago I need help with this question, The graph below shows the value of Edna's profits f(t), in dollars, after t months: graph of quadratic function f of t having x intercepts at 6, 0 and 18, 0, vertex at 12, negative 36, and passes through point 21, 41.25 What is the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month?

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1. anonymous

whees the graph??

2. anonymous

I don't know how to put it on here but the part that says graph of quadratic function f of x that is what is on the graph.

3. anonymous

click on attach file i can't understand u

4. anonymous

Oh ok sorry on my computer the screen is small so i didn't see that okay one sec and i will put the graph.

5. anonymous

ok :3

6. anonymous

7. anonymous

Here is the graph

8. anonymous

ok wait up

9. anonymous

ok

10. anonymous

rate of change= slope

11. anonymous

do you know how to find the slope?

12. anonymous

since you are not answering i will show ya

13. anonymous

slope=$\frac{ y2-y1 }{ x2-x1 }$

14. anonymous

so your two points from 18 months to 21 months is: (0,18) and (21,41.25).

15. anonymous

Hey sorry it wouldn't let me type lol

16. anonymous

plug the points into the slope formula and you get:$\frac{ 41.25-18 }{ 21-0 } =\frac{ 23.25 }{ 21 }$

17. anonymous

thats the rate o change :3

18. anonymous

g'night btw

19. anonymous

Oh okay thank you! Lol

20. anonymous

:)