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anonymous
 one year ago
1Using the words: odd; even; or neither, classify each of the following functions.U must provide supporting evidence for your classification?
1 f(x)  2x + 1
2 f(x) 4x^2  3
3 f(x) 3x^3  2x^2 + 5
4 f(x) 1/x^3 5x
anonymous
 one year ago
1Using the words: odd; even; or neither, classify each of the following functions.U must provide supporting evidence for your classification? 1 f(x)  2x + 1 2 f(x) 4x^2  3 3 f(x) 3x^3  2x^2 + 5 4 f(x) 1/x^3 5x

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.2for a function to be even f(x) = f(x) for an odd function f(x) =  f(x)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2so for Number 2 f(1) = 4(1)^2 3 = 4 3 = 1 f(1) = 4(1)^2  3 = 4  3 = 1 so this is an even function

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2even functions are symmetrical about the yaxis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What about the answer of 3 and 4 can you also help in it plz

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2and odd functions have got origin symmetry

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2find f(1) and f(1) for number 3 what do you get?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.23(1)^3  2((1)^2 + 5 = ? 3(1)^3  2((1)^2 + 5 = ?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2if it does ot fit the requirements for even and odd then it is neither

welshfella
 one year ago
Best ResponseYou've already chosen the best response.23(1)^3  2((1)^2 + 5 = 3  2 + 5 = 6 3(1)^3  2((1)^2 + 5 = 3 2 + 5 = 0

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2 so that is neither

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2sorry gotta go right now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and what abut fourth one ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thnak you for your help i ll try 4th by my self you are genius :)

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.0it's the same process as welsh said for a function to be even f(x) = f(x) for an odd function f(x) =  f(x) to see whether f(x) = 1/x^3 5x is even or odd, we can use two steps: 1. to test whether f(x) is even, evaluate f(1) and f(1). if they are the same, then the function is even. otherwise, the function is not even. 2. to test whether f(x) is odd, evaluate f(1) and f(1), if they are the same, then the function is odd. otherwise, the function is not odd

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so can you help in 4th one ?
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