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donnie1999

  • one year ago

-------- WILL MEDAL -------- -------- HELP PLEASE -------- Find the x-intercepts for the parabola defined by the equation below. y = x^2 - 9x + 18

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  1. donnie1999
    • one year ago
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    @butterflydreamer

  2. anonymous
    • one year ago
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    What do you think? What did you get after working it out?

  3. anonymous
    • one year ago
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    @UsukiDoll

  4. anonymous
    • one year ago
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    First ask your self what two factors when you times them equals 18 and also sums(add together) up to -9

  5. rishavraj
    • one year ago
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    to find x-intercept ...let y = 0

  6. rishavraj
    • one year ago
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    so solve x^2 - 9x + 18 = 0

  7. donnie1999
    • one year ago
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    i got (0,3) and (0,6)

  8. rishavraj
    • one year ago
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    dont u think it should be (3 , 0) and (6 , 0)???

  9. UsukiDoll
    • one year ago
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    to find x - intercept let the y = 0 (x^2-9x+18) = 0 so the y's have to be 0 you are solving for the x values

  10. UsukiDoll
    • one year ago
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    consider the 2 numbers 6 and 3. Those numbers work because 6 x 3 =18 (got my last term) 6+3 =9 (got my middle term) so now we can factor (x-6)(x-3) =0 so now we have 2 cases x - 6 =0 and x -3 =0 solve for x and we should have what @rishavraj said

  11. UsukiDoll
    • one year ago
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    the y is fixed at 0 for these cases... since we are looking for x-intercept

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