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anonymous

  • one year ago

What is the bond angle of a trigonal planar molecule, such as boron trifluoride (BF3)?

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  1. butterflydreamer
    • one year ago
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    boron fluoride , BF3, has3 fluorine atoms per 1 boron atom. it looks like this: |dw:1436880658455:dw| So to work out the bond angle, you know in one FULL revolution (like a complete circle), the angle sum = 360 degrees. We have 3 angles. So you just go: \[360 \div 3 = ?\]

  2. butterflydreamer
    • one year ago
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    trigonal planar -> a molecular geometry model with ONE atom at the center (Boron) and 3 atoms (Fluorine atoms) that form an EQUILATERAL TRIANGLE. All the bonds are 120 degrees because ALL 4 atoms lay flat on a plane |dw:1436881100737:dw|

  3. Photon336
    • one year ago
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    Boron makes three bonds to say Fluorine and has 0 Lone pairs. If you draw it out it would be trigonal planar. Remember the presence of lone pairs causes the bond angles to shrink as a way of minimizing the repulsions by that electron pair.

  4. anonymous
    • one year ago
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    thank you! @butterflydreamer

  5. butterflydreamer
    • one year ago
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    noooooo problem :)!

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