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axis of symmetry, x = -b/2a

where the general form of a parabola is y= ax^2+bx+c

Okay I know the vertex is 4,-8

well then the axis of symmetry is just the x value of the vertex

which is 4 my other problem was setting it up as an equation

y = (x-4)^2 - 8 this is what i have

yeah thats correct

though it says I was wrong when I tried to submit it

who says it was wrong?

when I try to submit my assignment it counts the equation wrong

that's what happen I have -4

ok, there you go

so its x=4

oh yes it is

it's right thank you :D

no problemo

although I have more questions I may need help on in a few minutes