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anonymous

  • one year ago

convert 0.004 g/(min.)(m^3)cm to lbm/(hr)(ft^3)

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  1. anonymous
    • one year ago
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    can you help me @ganeshie8 and @Michele_Laino :) i can do it if the given is g/(min.)(m^3) ,but there's a cm in the denominator :/

  2. Michele_Laino
    • one year ago
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    is your measure like this? \[\Large 0.04\frac{g}{{\min \times {m^3} \times cm}}\]

  3. anonymous
    • one year ago
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    yes :)

  4. Michele_Laino
    • one year ago
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    "lbm" stands for?

  5. anonymous
    • one year ago
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    pound (mass)

  6. Michele_Laino
    • one year ago
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    g stands for grams? right?

  7. anonymous
    • one year ago
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    yes :)

  8. Michele_Laino
    • one year ago
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    please wait, I'm working on your question

  9. anonymous
    • one year ago
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    it's okay and take your time, thank you for helping me :)

  10. Michele_Laino
    • one year ago
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    please note that, in the first unit measure, we divide by a length^4 whereas in the second unit of measure we divide by a length^3

  11. Michele_Laino
    • one year ago
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    since the second unit of measure is: \[\Large \frac{{{\text{lbm}}}}{{{\text{hour}} \cdot {\text{ fee}}{{\text{t}}^{\text{3}}}}}\]

  12. anonymous
    • one year ago
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    uhmm i'm sorry I didn't quite get it about dividiing by a length^4 part, can you show it to me. i'm really sorry :(

  13. Michele_Laino
    • one year ago
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    the first unit of measure is: \[\Large \frac{{{\text{grams}}}}{{{\text{min }} \times {{\text{m}}^{\text{3}}}{\text{ }} \times {\text{cm}}}}{\text{ = }}\frac{{{\text{mass}}}}{{{\text{time }} \times {\text{lengt}}{{\text{h}}^{\text{4}}}}}\]

  14. Michele_Laino
    • one year ago
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    m stands for meter, right?

  15. anonymous
    • one year ago
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    yes :)

  16. Michele_Laino
    • one year ago
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    so: m^3*cm = length^4

  17. anonymous
    • one year ago
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    \[4x10^-5 kg/(\min)(m^4) \times 60 \min./1hr \times 1lbm/0.4536 kg \times (0.3048m)^3/1ft.^3\]

  18. Michele_Laino
    • one year ago
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    so, there is not cm at the denominator?

  19. anonymous
    • one year ago
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    oops sorry i'll do it again i forgot to convert cm to m. am I doing it right?

  20. anonymous
    • one year ago
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    nope, it says on our worksheet that it's placed in the denominator :(

  21. Michele_Laino
    • one year ago
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    if the dimensions are not equal, we can not change from one unit of measure to another

  22. Michele_Laino
    • one year ago
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    maybe there is m^2 instead of m^3?

  23. anonymous
    • one year ago
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    i'll just ask my professor about this quetion, maybe it's a typographical error, it would be easier if cm is not present in the question :)))

  24. Michele_Laino
    • one year ago
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    ok!

  25. anonymous
    • one year ago
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    thank you so much for helping me :D

  26. Michele_Laino
    • one year ago
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    :)

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