## anonymous one year ago convert 0.004 g/(min.)(m^3)cm to lbm/(hr)(ft^3)

1. anonymous

can you help me @ganeshie8 and @Michele_Laino :) i can do it if the given is g/(min.)(m^3) ,but there's a cm in the denominator :/

2. Michele_Laino

is your measure like this? $\Large 0.04\frac{g}{{\min \times {m^3} \times cm}}$

3. anonymous

yes :)

4. Michele_Laino

"lbm" stands for?

5. anonymous

pound (mass)

6. Michele_Laino

g stands for grams? right?

7. anonymous

yes :)

8. Michele_Laino

9. anonymous

it's okay and take your time, thank you for helping me :)

10. Michele_Laino

please note that, in the first unit measure, we divide by a length^4 whereas in the second unit of measure we divide by a length^3

11. Michele_Laino

since the second unit of measure is: $\Large \frac{{{\text{lbm}}}}{{{\text{hour}} \cdot {\text{ fee}}{{\text{t}}^{\text{3}}}}}$

12. anonymous

uhmm i'm sorry I didn't quite get it about dividiing by a length^4 part, can you show it to me. i'm really sorry :(

13. Michele_Laino

the first unit of measure is: $\Large \frac{{{\text{grams}}}}{{{\text{min }} \times {{\text{m}}^{\text{3}}}{\text{ }} \times {\text{cm}}}}{\text{ = }}\frac{{{\text{mass}}}}{{{\text{time }} \times {\text{lengt}}{{\text{h}}^{\text{4}}}}}$

14. Michele_Laino

m stands for meter, right?

15. anonymous

yes :)

16. Michele_Laino

so: m^3*cm = length^4

17. anonymous

$4x10^-5 kg/(\min)(m^4) \times 60 \min./1hr \times 1lbm/0.4536 kg \times (0.3048m)^3/1ft.^3$

18. Michele_Laino

so, there is not cm at the denominator?

19. anonymous

oops sorry i'll do it again i forgot to convert cm to m. am I doing it right?

20. anonymous

nope, it says on our worksheet that it's placed in the denominator :(

21. Michele_Laino

if the dimensions are not equal, we can not change from one unit of measure to another

22. Michele_Laino

maybe there is m^2 instead of m^3?

23. anonymous

i'll just ask my professor about this quetion, maybe it's a typographical error, it would be easier if cm is not present in the question :)))

24. Michele_Laino

ok!

25. anonymous

thank you so much for helping me :D

26. Michele_Laino

:)