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anonymous

  • one year ago

What are the amplitude, period, phase shift, and midline of f(x) = −3 sin(4x − π) + 2?

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  1. anonymous
    • one year ago
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    What are the amplitude, period, phase shift, and midline of f(x) = −3 sin(4x − π) + 2? Amplitude: 3; period: pi over 2; phase shift: x = pi over 4; midline: y = 2 Amplitude: −3; period: pi over 2; phase shift: x = pi over 2; midline: y = 2 Amplitude: 2; period: pi over 4; phase shift: x = pi over 4; midline: y = −3 Amplitude: 2; period: pi over 4; phase shift: x = pi over 2; midline: y = −3

  2. anonymous
    • one year ago
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    @dan815 @mr_basketball27 Please help me.

  3. anonymous
    • one year ago
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    @acxbox22 @automaticloveletter @andreacastillol @AAlixH @adekker @batman19991 @BVB4life @hernandeze @poopsiedoodle @ganeshie8 @ganeshie8 @teagirl7630 @welshfella @ohsnapitsannie @Ihatehomework44649 @Thatkid_marc

  4. Jacob902
    • one year ago
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    heres an example What are the amplitude, period, phase shift, and midline of f(x) = -4 cos(3x - π) + 1?

  5. Jacob902
    • one year ago
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    : f(x) = -  4 cos(3x – π)  +  1   ...   in this form the characteristics are: amplitude = 4 period = 2π ⁄ 3 phase shift = -π radians vertical shift = +1 average = +1   =   midline ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ HOWEVER, because of the -π phase shift, this equation is equivalent to: y = 4 cos(3x)  +  1   ...   and in this form the characteristics are: amplitude = 4 period = 2π ⁄ 3 phase shift = 0 vertical shift = +1 average = +1   =   midline

  6. anonymous
    • one year ago
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    So what is next @Jacob902 ?

  7. anonymous
    • one year ago
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    So is the answer A?

  8. anonymous
    • one year ago
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    @pooja195 Would my answer be A?

  9. Jacob902
    • one year ago
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    yes

  10. anonymous
    • one year ago
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    Thanks

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