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anonymous
 one year ago
Let u = <4, 3>. Find the unit vector in the direction of u, and write your answer in component form.
anonymous
 one year ago
Let u = <4, 3>. Find the unit vector in the direction of u, and write your answer in component form.

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1the length of your vector is: \[\Large \left\ u \right\ = \sqrt {{{\left( {  4} \right)}^2} + {{\left( {  3} \right)}^2}} = \sqrt {16 + 9} = 5\] now you have to divide your vector by its length

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1namely, what is: \[\Large \frac{u}{{\left\ u \right\}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i put it in component form?? @Michele_Laino

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is simple: \[\Large \frac{u}{{\left\ u \right\}} = \frac{{ <  4,  3 > }}{5} = < \frac{{  4}}{5},\frac{{  3}}{5} > \]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that procedure above is the division of a vector by a real number, which is always possible when, as in our case, that real number is different from zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh okay thank you @Michele_Laino
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