YumYum247
  • YumYum247
help!!!!
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
YumYum247
  • YumYum247
1 Attachment
YumYum247
  • YumYum247
@gleem
YumYum247
  • YumYum247
can you please check my work????????

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

YumYum247
  • YumYum247
@dan815 can you please check my work????
anonymous
  • anonymous
looks good until the last step. I think you miscopied a previous result.
YumYum247
  • YumYum247
please help me what did i do wrong????
YumYum247
  • YumYum247
@Michele_Laino
YumYum247
  • YumYum247
@IrishBoy123 help please!!!
YumYum247
  • YumYum247
@welshfella
YumYum247
  • YumYum247
@shamim
YumYum247
  • YumYum247
@Jaynator495
anonymous
  • anonymous
0.342m/4 = 0.0855 m
YumYum247
  • YumYum247
ok i didn't know about this equation, what is it used for???? f1=v4L
YumYum247
  • YumYum247
can you please list all the formulas necessary related to this unit.
IrishBoy123
  • IrishBoy123
the closed pipe [closed at one end] has a constraint at the closed end, which must be a node. the fundamental resonance occurs when \(\lambda = 4L\)
IrishBoy123
  • IrishBoy123
as \(v = f.\lambda\), then \(\lambda_1 = \frac{v}{f}\) and \(L_1 = \frac{v}{4*f}\)
YumYum247
  • YumYum247
can you please tell me how a fundamental resonance occur when λ=4L with a quick sketch!!!
IrishBoy123
  • IrishBoy123
look at this: http://hyperphysics.phy-astr.gsu.edu/hbase/waves/clocol.html this site is generally great for illustrations/pictures/diagrams
IrishBoy123
  • IrishBoy123
|dw:1436898866645:dw|
YumYum247
  • YumYum247
oh i got it.... o_o
YumYum247
  • YumYum247
so the minimum length in this case would be the length of the fundamental
YumYum247
  • YumYum247
ok let me watch a tutorial on this topic and nopefuly it'll help me clearfy the misconceptions i have.....Thanks tho!!
IrishBoy123
  • IrishBoy123
yes. get you're head around the science and the formulae you can build .... the locations of the nodes are key.

Looking for something else?

Not the answer you are looking for? Search for more explanations.