Destinyyyy
  • Destinyyyy
Find the coordinates of the vertex and the intercepts of the following quadratic function. When necessary, approximate the x-intercepts to the nearest tenth.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Destinyyyy
  • Destinyyyy
f(x)+x^2+6x+5
Destinyyyy
  • Destinyyyy
a=1 b=6 c=5 =-(6)/2(1)
princeharryyy
  • princeharryyy
y = (x+1)(x+5), I guess you can solve the rest by yourself

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Destinyyyy
  • Destinyyyy
??
princeharryyy
  • princeharryyy
f(x)+x^2+6x+5 can be expressed as y = (x+1)(x+5)
Destinyyyy
  • Destinyyyy
Um okay.. This is my first problem with this. And I basically have no clue as to what im doing. And what your saying doesnt follow my examples and you haven't said anything about what ive already solved.
Destinyyyy
  • Destinyyyy
It says to solve for the vertex with x=-b/2a Then plug the answer for x into the problem to get the y-intercept. Factor, then set each factor to 0, that gives the answer x-intercept.
princeharryyy
  • princeharryyy
it's a point where you get the maxima or minima
princeharryyy
  • princeharryyy
|dw:1436900448579:dw|
princeharryyy
  • princeharryyy
hope it helps!
Destinyyyy
  • Destinyyyy
I guess.. Now what?
princeharryyy
  • princeharryyy
intercepts (-5,0) and (-1,0) for vertex put x = -3 in the equation find y y = (-3+1)(-3+5) = -4 so vertex (-3,-4)
Destinyyyy
  • Destinyyyy
Um why are you doing it with y? My examples show to do it like this-- f(-3)= (-3)^2 -6(-3)+5
princeharryyy
  • princeharryyy
y = f(x) they are both the same
princeharryyy
  • princeharryyy
we write it like this >> y = f(x) = (x+1)(x+5) y is a function in x

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