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anonymous

  • one year ago

*** I know this a different subject.*** If it requires 23.4 milliliters of 0.65 molar barium hydroxide to neutralize 42.5 milliliters of nitric acid, solve for the molarity of the nitric acid solution. Show all of the work used to solve this problem. Unbalanced equation: Ba(OH)2 + HNO3 Ba(NO3)2 + H2O

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  1. pratyush5
    • one year ago
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    I am guessing you are unfamiliar with normality and equivalent concept right ?

  2. anonymous
    • one year ago
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    A bit

  3. anonymous
    • one year ago
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    I know stoichiometry

  4. pratyush5
    • one year ago
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    Don't worry, I'll do this with mole concept

  5. anonymous
    • one year ago
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    but I don't know on how to start

  6. pratyush5
    • one year ago
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    So first of all - Molarity X Volume = No of moles right ?

  7. anonymous
    • one year ago
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    Not yet

  8. anonymous
    • one year ago
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    Unless it is 0.65

  9. pratyush5
    • one year ago
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    Why this is definiton of molarity

  10. pratyush5
    • one year ago
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    I wasnt referring to question. Just a general insight.

  11. pratyush5
    • one year ago
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    |dw:1436897699148:dw|

  12. anonymous
    • one year ago
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    Yes its is Balanced Equation: Ba(OH)2 2HNO3 ---> Ba(NO3)2 2H2O

  13. pratyush5
    • one year ago
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    What I am trying to say is you know the no of moles of barium hydroxide. Then from balanced eqaution you get moles of nitric acid corresponding to one mole of barium hydroxide. Then you equate moles by unitary method

  14. pratyush5
    • one year ago
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    Good ! Now as you can see that 1 mole of Baoh2 reacts with 2 moles of nitric acid So 15.21 millimoles will react with 30.42 millimoles ?

  15. anonymous
    • one year ago
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    What unit 15.21 would be in

  16. pratyush5
    • one year ago
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    millimoles. Because you are multipling molarity with millilitres

  17. pratyush5
    • one year ago
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    Any doubt ?

  18. anonymous
    • one year ago
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    ok so it is15.21 mmol Ba(OH)2

  19. pratyush5
    • one year ago
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    Yes

  20. pratyush5
    • one year ago
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    SO now from balanced equation we need double the millimoles of nitric acid ?

  21. anonymous
    • one year ago
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    ok

  22. anonymous
    • one year ago
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    30.42

  23. pratyush5
    • one year ago
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    So we need 30.42 millimoles of nitric acid |dw:1436898445233:dw|

  24. pratyush5
    • one year ago
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    Feel free to ask any doubts ?

  25. anonymous
    • one year ago
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    I got 0.71576471

  26. pratyush5
    • one year ago
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    Yeah that'd be the right answer.

  27. anonymous
    • one year ago
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    Thank you very much.

  28. pratyush5
    • one year ago
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    You are welcome :)

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