What is the number of ways to arrange 8 objects from a set of 12 different objects?

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What is the number of ways to arrange 8 objects from a set of 12 different objects?

Mathematics
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You can use here the concept of Combinations..
12 possible first objects leaves 11 possible second objects leaves 10 possible third objects etc. 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 = 12! / (12 - 8)!
well since theres a to choose do 12*11*10*9*8*7*6*5=what @thisotherliz

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Other answers:

You want to just arrange them: So, the number of ways in which \(r\) objects can be arranged from \(n\) different objects is given by: \[\large \implies ^nC_r\]
what did u get @thisotherliz
19958400 thank you all
\[Also \quad \color{green}{^nC_r = \frac{n!}{(n-r)! \cdot r!}}\]
np dont forget to medal if u need more help just mention me
I think that is a wrong answer...
\[^12C_8 = \frac{12!}{5! \times 8!} = \frac{12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times1} = ??\]
\[^{12}C_8\]
I am wrong.. :P
My mind has got rusty.. :) What the hell yaar..!! Sorry, you all are good.. :)

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