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anonymous
 one year ago
What is the number of ways to arrange 8 objects from a set of 12 different objects?
anonymous
 one year ago
What is the number of ways to arrange 8 objects from a set of 12 different objects?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can use here the concept of Combinations..

Jacob902
 one year ago
Best ResponseYou've already chosen the best response.112 possible first objects leaves 11 possible second objects leaves 10 possible third objects etc. 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 = 12! / (12  8)!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well since theres a to choose do 12*11*10*9*8*7*6*5=what @thisotherliz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You want to just arrange them: So, the number of ways in which \(r\) objects can be arranged from \(n\) different objects is given by: \[\large \implies ^nC_r\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what did u get @thisotherliz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.019958400 thank you all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[Also \quad \color{green}{^nC_r = \frac{n!}{(nr)! \cdot r!}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0np dont forget to medal if u need more help just mention me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think that is a wrong answer...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[^12C_8 = \frac{12!}{5! \times 8!} = \frac{12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times1} = ??\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My mind has got rusty.. :) What the hell yaar..!! Sorry, you all are good.. :)
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