## anonymous one year ago What is the number of ways to arrange 8 objects from a set of 12 different objects?

1. anonymous

You can use here the concept of Combinations..

2. Jacob902

12 possible first objects leaves 11 possible second objects leaves 10 possible third objects etc. 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 = 12! / (12 - 8)!

3. anonymous

well since theres a to choose do 12*11*10*9*8*7*6*5=what @thisotherliz

4. anonymous

You want to just arrange them: So, the number of ways in which $$r$$ objects can be arranged from $$n$$ different objects is given by: $\large \implies ^nC_r$

5. anonymous

what did u get @thisotherliz

6. anonymous

19958400 thank you all

7. anonymous

$Also \quad \color{green}{^nC_r = \frac{n!}{(n-r)! \cdot r!}}$

8. anonymous

np dont forget to medal if u need more help just mention me

9. anonymous

I think that is a wrong answer...

10. anonymous

$^12C_8 = \frac{12!}{5! \times 8!} = \frac{12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times1} = ??$

11. anonymous

$^{12}C_8$

12. anonymous

I am wrong.. :P

13. anonymous

My mind has got rusty.. :) What the hell yaar..!! Sorry, you all are good.. :)