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anonymous

  • one year ago

What is the number of ways to arrange 8 objects from a set of 12 different objects?

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  1. anonymous
    • one year ago
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    You can use here the concept of Combinations..

  2. Jacob902
    • one year ago
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    12 possible first objects leaves 11 possible second objects leaves 10 possible third objects etc. 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 = 12! / (12 - 8)!

  3. anonymous
    • one year ago
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    well since theres a to choose do 12*11*10*9*8*7*6*5=what @thisotherliz

  4. anonymous
    • one year ago
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    You want to just arrange them: So, the number of ways in which \(r\) objects can be arranged from \(n\) different objects is given by: \[\large \implies ^nC_r\]

  5. anonymous
    • one year ago
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    what did u get @thisotherliz

  6. anonymous
    • one year ago
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    19958400 thank you all

  7. anonymous
    • one year ago
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    \[Also \quad \color{green}{^nC_r = \frac{n!}{(n-r)! \cdot r!}}\]

  8. anonymous
    • one year ago
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    np dont forget to medal if u need more help just mention me

  9. anonymous
    • one year ago
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    I think that is a wrong answer...

  10. anonymous
    • one year ago
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    \[^12C_8 = \frac{12!}{5! \times 8!} = \frac{12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times1} = ??\]

  11. anonymous
    • one year ago
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    \[^{12}C_8\]

  12. anonymous
    • one year ago
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    I am wrong.. :P

  13. anonymous
    • one year ago
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    My mind has got rusty.. :) What the hell yaar..!! Sorry, you all are good.. :)

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