## anonymous one year ago Solve this using pascal's triangle (2x+3)^5

1. anonymous

@misssunshinexxoxo

2. zzr0ck3r

$$(2x+3)^5$$ First write out the polynomial without the coefficients. i.e. without the triangle part yet $$(2x)^5+(2x)^43+(2x)^33^2+(2x)^23^3+(2x)3^4+3^5$$ Then use the triangle to get the coefficients $$32(2x)^5+5*32(2x)^43+\frac{4*5*32}{2}(2x)^33^2+\frac{4*5*32}{2}(2x)^23^3+5*32(2x)3^4+3^5$$