Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child?
4 over 12 plus 3 over 12 is equal to 7 over 12
4 over 12 plus 3 over 11 is equal to 80 over 132
4 over 12 multiplied by 3 over 12 is equal to 12 over 144
4 over 12 multiplied by 3 over 11 is equal to 12 over 132
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well there are 4 blue 3 yellow and 12 total at first so write 4/12 for the first kid then since the kid took it now there is only 11 total so 3/11 for the second kid now multiply across in
4/12*3/11 or 3*4 and 12*11 what do u get for those two equations 4*3 and 11*12 @liana1026
@liana dont dont forget to medal and fan if u havent yet also mention me if u need more help
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thats really confusing i was thinking the answer was c but idk
no its d
its 4/12 because there are 4 blue and 12 total so a 4 out of 12 chance then a kid takes the marble so now there is only 11 marbles total and 3 yellow so 3/11 and a 3 out of 11 chance now u cross multiply 4*3=12 and 11*12=132 so 12/132