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Blondisaurus
 one year ago
How would you go about solving this equation for x? (In comments)
Blondisaurus
 one year ago
How would you go about solving this equation for x? (In comments)

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Blondisaurus
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x }{ x3 } = \frac{ 3 }{ x3 }+9 \]

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{x}{x3}=\frac{3}{x3}+9\\\]first note that x cant be 3 now lets go \[\frac{x}{x3}\frac{3}{x3}=9\\\frac{x3}{x3}=9\\x \neq 3\\we \\can\\simplify\\1=9\\\] and it has no roots

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.2another method multiply by (x3) \[(x3)(\frac{x}{x3}=\frac{3}{x3}+9)\\x=3+9(x3)\\x9x=27+3\\8x=24\\x=3\] but \[x \neq 3\\\] because denominator goes to zero

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.2the equation has no root

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it's simply like that 2=2+1, which is false equation. above is conditional equation with no solution.
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