## YumYum247 one year ago Yelp!!!!

1. YumYum247

@IrishBoy123 help check my work please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2. YumYum247

i tink i know my mistake!!!!

3. YumYum247

it should have been f3=5((346m/sec)/2(0.54m) )

4. YumYum247

never mind i take that back!!! that's for the closed harmonic!!! LOL :"D

5. YumYum247

f3=3((346m/sec)/2(0.54m) ) this is right...!!!

6. YumYum247

in a closed air column each harmonic occurs at 1 3 5 7 pattern where as the open doesn't

7. YumYum247

@IrishBoy123 are you there?!?!?!?!!?!? O-O

8. IrishBoy123

go back to basics and draw the wave shapes starting from the given that v = const and v = $$f.\lambda$$ we get v = $$f_n.\lambda_n$$ and, for the harmonics for an open air column: $$L = \lambda_1/2 = 2\lambda_2/2=3\lambda_3/2 = 4\lambda_4/2 = \ ...n\lambda_n/2$$ for the 3rd harmonic, $$f_3 = v / \lambda_3 = \frac { v }{\frac{2L}{3}} = \frac{3v}{2L}$$ $$f_3 = \frac{3*346}{2*0.54} = 961Hz$$

9. IrishBoy123

harmonics for open ended go in halves: http://hyperphysics.phy-astr.gsu.edu/hbase/waves/opecol.html#c3 everything else follows from that

10. YumYum247

LOL yah sorry i kinda confused my self but that's what i got!!!! :"D i watched a really nice video on this topic and it did a great deal of help!!!!