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anonymous

  • one year ago

log9(x+6)-log9x=log9 2

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  1. anonymous
    • one year ago
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    9 is base I'm just asking whether this is even solvable

  2. zzr0ck3r
    • one year ago
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    hint \(\log_9(x+6)-\log_9(x)=\log_9(2)\\\log_9(\frac{x+6}{x})=\log_9(2)\\\frac{x+6}{x}=2\)

  3. zzr0ck3r
    • one year ago
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    can you solve that?

  4. anonymous
    • one year ago
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    that's what i ended up with

  5. zzr0ck3r
    • one year ago
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    good work

  6. anonymous
    • one year ago
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    well then what do you put as final answer just that?

  7. zzr0ck3r
    • one year ago
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    you can always check to see if your right here http://www.wolframalpha.com/input/?i=log9%28x%2B6%29-log9%28x%29%3Dlog9%282%29

  8. zzr0ck3r
    • one year ago
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    no

  9. zzr0ck3r
    • one year ago
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    solve for x

  10. zzr0ck3r
    • one year ago
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    \(\dfrac{x+6}{x}=2\)

  11. zzr0ck3r
    • one year ago
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    multiply both sides by \(x\) \(x+6=2x\)

  12. anonymous
    • one year ago
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    u end up with 6=2?

  13. anonymous
    • one year ago
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    oooh

  14. zzr0ck3r
    • one year ago
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    no of course not, 6 is not equal to 2

  15. anonymous
    • one year ago
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    ima dumbass

  16. zzr0ck3r
    • one year ago
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    if you are having problems solving this, I would go back and review old material. You should not be working on logs if you cant solve this IMO

  17. zzr0ck3r
    • one year ago
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    \(x+6=2x \implies x=6\)

  18. anonymous
    • one year ago
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    lol thanks for the help

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spraguer (Moderator)
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