## anonymous one year ago log9(x+6)-log9x=log9 2

1. anonymous

9 is base I'm just asking whether this is even solvable

2. zzr0ck3r

hint $$\log_9(x+6)-\log_9(x)=\log_9(2)\\\log_9(\frac{x+6}{x})=\log_9(2)\\\frac{x+6}{x}=2$$

3. zzr0ck3r

can you solve that?

4. anonymous

that's what i ended up with

5. zzr0ck3r

good work

6. anonymous

well then what do you put as final answer just that?

7. zzr0ck3r

you can always check to see if your right here http://www.wolframalpha.com/input/?i=log9%28x%2B6%29-log9%28x%29%3Dlog9%282%29

8. zzr0ck3r

no

9. zzr0ck3r

solve for x

10. zzr0ck3r

$$\dfrac{x+6}{x}=2$$

11. zzr0ck3r

multiply both sides by $$x$$ $$x+6=2x$$

12. anonymous

u end up with 6=2?

13. anonymous

oooh

14. zzr0ck3r

no of course not, 6 is not equal to 2

15. anonymous

ima dumbass

16. zzr0ck3r

if you are having problems solving this, I would go back and review old material. You should not be working on logs if you cant solve this IMO

17. zzr0ck3r

$$x+6=2x \implies x=6$$

18. anonymous

lol thanks for the help