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anonymous

  • one year ago

I will give a medal to ever answers this. Kathy wants to factor x2 – 12x + 36 by grouping; however, Tom says it is a special product and can factor a different way. Using complete sentences explain and demonstrate how both methods will result in the same factors.

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  1. Mertsj
    • one year ago
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    Kathy wants to replace -12x with -6x-6x so she will have: x^2-6x-6x+36 She will then group the first two terms and the last two terms using the associative property to get: (x^2-6x)+(-6x+36) The first two terms have the common factor x. The last two terms have the common factor -6. Kathy will factor those out and get: x(x-6)-6(x-6) She now has an expression with two terms. The two terms have the common factor x-6. Factoring it out, Kathy has: (x-6)(x-6).

  2. anonymous
    • one year ago
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    Thank you.

  3. Mertsj
    • one year ago
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    Tom recognizes that x^2-12x+36 is of the form a^2-2ab +b^2 whose factors are (a-b)^2 where a = x and b = 6. He replaces a with x and b with 6 to get the factors (x-6)^2.

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