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anonymous
 one year ago
Medal will be given,
Roy exclaims that his quadratic with a discriminant of –9 has no real solutions. Roy then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Roy, in calm and complete sentences, how to find the solutions, even though they are not real
anonymous
 one year ago
Medal will be given, Roy exclaims that his quadratic with a discriminant of –9 has no real solutions. Roy then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Roy, in calm and complete sentences, how to find the solutions, even though they are not real

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2How do express a calm sentence in writing?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1general form of a quadratic equation is ax^2 + bx + c and the discriminant is square root(b^24ac) you can pick three values of a, b, and c such that square root(b^24ac) is positive

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1we can still use the quadratic formula to find the solutions, like we would with real solutions, but we'll need to evaluate the nonreal discriminant

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436918739549:dw

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0actually Roy is correct btw surely, there are "imaginary" solutions but Roy said there were no "real" ones, and he's correct

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Here is the quadratic formula: \(x = \dfrac{b \pm \sqrt{b^2  4ac}}{2a} \) It is the solution to a quadratic equation of the form: \(ax^2 + bx + c = 0\) Notice that the quadratic formula contains the part \(b^2  4ac\) inside the root. If you pick numbers for a and c that when multiplied together and subtracted from \(b^2\) will result in a negative number, a negative discriminant, then the solutions to the quadratic equation will definitely be complex.

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.1yeah, listen to mathstudent's answer, it's better than mine
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