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anonymous

  • one year ago

Medal will be given, Roy exclaims that his quadratic with a discriminant of –9 has no real solutions. Roy then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Roy, in calm and complete sentences, how to find the solutions, even though they are not real

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  1. mathstudent55
    • one year ago
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    How do express a calm sentence in writing?

  2. Vocaloid
    • one year ago
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    general form of a quadratic equation is ax^2 + bx + c and the discriminant is square root(b^2-4ac) you can pick three values of a, b, and c such that square root(b^2-4ac) is positive

  3. Vocaloid
    • one year ago
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    we can still use the quadratic formula to find the solutions, like we would with real solutions, but we'll need to evaluate the nonreal discriminant

  4. Vocaloid
    • one year ago
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    |dw:1436918739549:dw|

  5. jdoe0001
    • one year ago
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    actually Roy is correct btw surely, there are "imaginary" solutions but Roy said there were no "real" ones, and he's correct

  6. mathstudent55
    • one year ago
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    Here is the quadratic formula: \(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) It is the solution to a quadratic equation of the form: \(ax^2 + bx + c = 0\) Notice that the quadratic formula contains the part \(b^2 - 4ac\) inside the root. If you pick numbers for a and c that when multiplied together and subtracted from \(b^2\) will result in a negative number, a negative discriminant, then the solutions to the quadratic equation will definitely be complex.

  7. anonymous
    • one year ago
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    Okay, Thank you.

  8. Vocaloid
    • one year ago
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    yeah, listen to mathstudent's answer, it's better than mine

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