anonymous
  • anonymous
Medal will be given, Roy exclaims that his quadratic with a discriminant of –9 has no real solutions. Roy then puts down his pencil and refuses to do any more work. Create an equation with a negative discriminant. Then explain to Roy, in calm and complete sentences, how to find the solutions, even though they are not real
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
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mathstudent55
  • mathstudent55
How do express a calm sentence in writing?
Vocaloid
  • Vocaloid
general form of a quadratic equation is ax^2 + bx + c and the discriminant is square root(b^2-4ac) you can pick three values of a, b, and c such that square root(b^2-4ac) is positive
Vocaloid
  • Vocaloid
we can still use the quadratic formula to find the solutions, like we would with real solutions, but we'll need to evaluate the nonreal discriminant

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Vocaloid
  • Vocaloid
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jdoe0001
  • jdoe0001
actually Roy is correct btw surely, there are "imaginary" solutions but Roy said there were no "real" ones, and he's correct
mathstudent55
  • mathstudent55
Here is the quadratic formula: \(x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \) It is the solution to a quadratic equation of the form: \(ax^2 + bx + c = 0\) Notice that the quadratic formula contains the part \(b^2 - 4ac\) inside the root. If you pick numbers for a and c that when multiplied together and subtracted from \(b^2\) will result in a negative number, a negative discriminant, then the solutions to the quadratic equation will definitely be complex.
anonymous
  • anonymous
Okay, Thank you.
Vocaloid
  • Vocaloid
yeah, listen to mathstudent's answer, it's better than mine

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