## anonymous one year ago ophia invested some money in a bank at a fixed rate of interest compounded annually. The equation below shows the value of her investment after x years: f(x) = 500(1.05)x What was the average rate of change of the value of Sophia's investment from the second year to the fourth year? 14.13 dollars per year 28.25 dollars per year 50.00 dollars per year 56.50 dollars per year

1. misty1212

HI!!

2. anonymous

hi :)

3. misty1212

average is $\frac{f(4)-f(2)}{4-2}$

4. anonymous

i would use a calculator

5. misty1212

i would use wolfram, it is right on the computer

6. anonymous

i need an explaination on how to do this :(

7. anonymous

ill just yolo it, thanks though

8. jim_thompson5910

f(x) = 500(1.05)^x f(2) = 500(1.05)^2 ... replace every x with 2 now use a calculator to evaluate 500(1.05)^2 if you don't have one, you can use a free online one like this http://web2.0calc.com/ type in 500(1.05)^2 then hit enter or the equal sign. Tell me what you get so I can check to see if it's correct or not.

9. anonymous

thank you :)