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anonymous
 one year ago
ophia invested some money in a bank at a fixed rate of interest compounded annually. The equation below shows the value of her investment after x years:
f(x) = 500(1.05)x
What was the average rate of change of the value of Sophia's investment from the second year to the fourth year?
14.13 dollars per year
28.25 dollars per year
50.00 dollars per year
56.50 dollars per year
anonymous
 one year ago
ophia invested some money in a bank at a fixed rate of interest compounded annually. The equation below shows the value of her investment after x years: f(x) = 500(1.05)x What was the average rate of change of the value of Sophia's investment from the second year to the fourth year? 14.13 dollars per year 28.25 dollars per year 50.00 dollars per year 56.50 dollars per year

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.0average is \[\frac{f(4)f(2)}{42}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i would use a calculator

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0i would use wolfram, it is right on the computer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need an explaination on how to do this :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ill just yolo it, thanks though

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1f(x) = 500(1.05)^x f(2) = 500(1.05)^2 ... replace every x with 2 now use a calculator to evaluate `500(1.05)^2` if you don't have one, you can use a free online one like this http://web2.0calc.com/ type in `500(1.05)^2` then hit enter or the equal sign. Tell me what you get so I can check to see if it's correct or not.
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