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anonymous

  • one year ago

ophia invested some money in a bank at a fixed rate of interest compounded annually. The equation below shows the value of her investment after x years: f(x) = 500(1.05)x What was the average rate of change of the value of Sophia's investment from the second year to the fourth year? 14.13 dollars per year 28.25 dollars per year 50.00 dollars per year 56.50 dollars per year

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  1. misty1212
    • one year ago
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    HI!!

  2. anonymous
    • one year ago
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    hi :)

  3. misty1212
    • one year ago
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    average is \[\frac{f(4)-f(2)}{4-2}\]

  4. anonymous
    • one year ago
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    i would use a calculator

  5. misty1212
    • one year ago
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    i would use wolfram, it is right on the computer

  6. anonymous
    • one year ago
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    i need an explaination on how to do this :(

  7. anonymous
    • one year ago
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    ill just yolo it, thanks though

  8. jim_thompson5910
    • one year ago
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    f(x) = 500(1.05)^x f(2) = 500(1.05)^2 ... replace every x with 2 now use a calculator to evaluate `500(1.05)^2` if you don't have one, you can use a free online one like this http://web2.0calc.com/ type in `500(1.05)^2` then hit enter or the equal sign. Tell me what you get so I can check to see if it's correct or not.

  9. anonymous
    • one year ago
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    thank you :)

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