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chrisGA

  • one year ago

Student Amber Ben Carter Description Amber shared her photo with 3 people. They continued to share it, so the number of shares increases every day as shown by the function. Ben shared his post with 2 friends. Each of those friends shares with 3 more every day, so the number of shares triples every day. Carter shared his post with 10 friends, who each share with only 2 people each day. Social Media Post Shares f(x) = 3(4)x Day Number of Shares 0 2 1 6 2 18 Carter shared his post with 10 friends, who each share with only 2 people each day.

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  1. chrisGA
    • one year ago
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    1) Using the functions for each student, predict how many shares each student's post will have received on Day 3 and then on Day 10. Justify your answers. 2)Graph each function using at least 3 points for each line. All graphs should be placed together on the same coordinate plane, so be sure to label each line. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology

  2. chrisGA
    • one year ago
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    can someone help me out or answer this for me i will give medal and fan please and thank you

  3. ganeshie8
    • one year ago
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    First read the problem and figure out what exactly it is asking to find out

  4. chrisGA
    • one year ago
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    it asking for how many shares each student's post will have received on Day 3 and then on Day 10

  5. ganeshie8
    • one year ago
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    Yes, we have 3 students : Amber, Ben, Carter Amber's shares function is given by \[f(x) = 3*(4)^x\] simply plugin \(x=3\) to find the number of shares on day \(3\)

  6. chrisGA
    • one year ago
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    so that amber share?

  7. chrisGA
    • one year ago
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    so all you have to do is plugin

  8. ganeshie8
    • one year ago
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    Right, you do see that function notation is so simple. All you have to do is plug because, when you plugin the day number, "x", the function f(x) spits out the shares on that day.

  9. chrisGA
    • one year ago
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    yes i see..How about number 2?

  10. chrisGA
    • one year ago
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    @ganeshie8

  11. ganeshie8
    • one year ago
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    have you finished with part1 ?

  12. chrisGA
    • one year ago
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    yes

  13. chrisGA
    • one year ago
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    Can you help with 2 now

  14. ganeshie8
    • one year ago
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    could you show me your work for part1

  15. chrisGA
    • one year ago
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    Amber=f(x)=3∗(4)x Ben=f(x)=2∗(4)x Carter=f(x)=10∗(4)x

  16. ganeshie8
    • one year ago
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    Not quite, Ben's shares are tripling each day, so the function should be \[f(x) = 2*(3)^x\] yes ?

  17. chrisGA
    • one year ago
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    yes

  18. ganeshie8
    • one year ago
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    your function for Carter also doesnt look correct

  19. ganeshie8
    • one year ago
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    `Carter shared his post with 10 friends, who each share with only 2 people each day.` each are sharing with 2 people each day, that means the number of shares are doubling each day, so the function for carter's shares will be \[f(x) = 10*(2)^x\]

  20. ganeshie8
    • one year ago
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    plugin x=3, 10 in each of these functions to find the number of shares on 3rd and 10th day

  21. chrisGA
    • one year ago
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    so it will be f(x)=10∗(2)x??

  22. ganeshie8
    • one year ago
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    for Carter, it is f(x) = 10*(2)^x

  23. ganeshie8
    • one year ago
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    Amber=f(x)=3∗(4)^x Ben=f(x)=2∗(3)x Carter=f(x)=10∗(2)^x plugin x=3 and find the number of shares on 3rd day

  24. chrisGA
    • one year ago
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    ok

  25. ganeshie8
    • one year ago
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    work it

  26. ganeshie8
    • one year ago
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    Amber=f(x)=3∗(4)^x plugin x = 3 : f(3) = 3*(4)^3 = ?

  27. chrisGA
    • one year ago
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    so just solve that?

  28. chrisGA
    • one year ago
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    192?

  29. ganeshie8
    • one year ago
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    Yes, so on day 3, Amber's photo will be shared to 192 people.

  30. ganeshie8
    • one year ago
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    similarly find out the number of shares on day 3 for Ben and Carter also

  31. chrisGA
    • one year ago
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    ok

  32. chrisGA
    • one year ago
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    ben=52 carter=20

  33. ganeshie8
    • one year ago
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    doesn't look correct, try again

  34. chrisGA
    • one year ago
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    for both?

  35. ganeshie8
    • one year ago
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    Amber=f(x)=3∗(4)^x Ben=f(x)=2∗(3)x Carter=f(x)=10∗(2)^x On 3rd day : Amber=f(3)=3∗(4)^3 = 192 Ben=f(x)=2∗(3)^3 = ? Carter=f(x)=10∗(2)^3 = ?

  36. chrisGA
    • one year ago
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    ben=54 carter=80

  37. ganeshie8
    • one year ago
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    Looks good! similarly work for day 10 also

  38. ganeshie8
    • one year ago
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    Amber=f(x)=3∗(4)^x Ben=f(x)=2∗(3)x Carter=f(x)=10∗(2)^x On 3rd day : Amber=f(3)=3∗(4)^3 = 192 Ben=f(x)=2∗(3)^3 = 54 Carter=f(x)=10∗(2)^3 = 80 On 10th day : Amber=f(10)=3∗(4)^10 = ? Ben=f(10)=2∗(3)^10 = ? Carter=f(10)=10∗(2)^10 = ?

  39. chrisGA
    • one year ago
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    am i doing the same thing or evaluate?

  40. ganeshie8
    • one year ago
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    Yes

  41. chrisGA
    • one year ago
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    samething? or evaluate??

  42. ganeshie8
    • one year ago
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    ofcourse you need to evaluate to know the shares on 10th day

  43. chrisGA
    • one year ago
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    carter=10240 ben=118098 Amber=3145728

  44. ganeshie8
    • one year ago
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    good, so who has more shares on day 10 ?

  45. ganeshie8
    • one year ago
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    Amber=f(x)=3∗(4)^x Ben=f(x)=2∗(3)x Carter=f(x)=10∗(2)^x On 3rd day : Amber=f(3)=3∗(4)^3 = 192 Ben=f(x)=2∗(3)^3 = 54 Carter=f(x)=10∗(2)^3 = 80 On 10th day : Amber=f(10)=3∗(4)^10 = 3145728 Ben=f(10)=2∗(3)^10 = 118098 Carter=f(10)=10∗(2)^10 = 10240

  46. chrisGA
    • one year ago
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    Amber

  47. ganeshie8
    • one year ago
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    Yes! why do you think Amber has more shares on day 10 ? Notice that Amber has started with just 3 shares and Carter started with 10 shares. Still Carter's shares are very low compared to Amber on day 10. why ?

  48. chrisGA
    • one year ago
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    becuase as the days went on People started to share amber post more than everyone else

  49. ganeshie8
    • one year ago
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    Kindof, but a more correct answer would be : Amber's shares are incresing by 4 times each day where as Carter's shares are only increasing by 2 times each day. so Amber's shares are expected to be more on day 10 compared to Carter's

  50. ganeshie8
    • one year ago
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    we're done with part1

  51. ganeshie8
    • one year ago
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    for part2, use desmos to graph the 3 functions https://www.desmos.com/calculator

  52. chrisGA
    • one year ago
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    i dont know how to use it can you show me the 1st one?

  53. chrisGA
    • one year ago
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    @ganeshie8

  54. ganeshie8
    • one year ago
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    do you see a textbox on top right corner ?

  55. ganeshie8
    • one year ago
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    enter the function there `f(x)=3∗(4)^x`

  56. ganeshie8
    • one year ago
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    https://www.desmos.com/calculator/fxnt3ldndm

  57. ganeshie8
    • one year ago
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    I have plotted the graph of Amber's shares for you above

  58. chrisGA
    • one year ago
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    https://www.desmos.com/calculator/3t1miijac8

  59. ganeshie8
    • one year ago
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    Looks perfect! maybe zoomout the graph a bit if you want... take a screenshot and attach it for part2

  60. chrisGA
    • one year ago
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    Thank you alot I really appreciate you taking the time to help me understand

  61. anonymous
    • one year ago
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    f Amber decides to mail copies of her photo to the 45 residents of her grandmother's assisted living facility, the new function representing her photo shares is f(x) = 3(4)x + 45. How does this graph compare with the original graph of Amber's photo share?

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