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anonymous

  • one year ago

Perform the requested operation or operations. (5 points) f(x) =(x-3)/8 ; g(x) = 8x + 3, find g(f(x)).

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  1. anonymous
    • one year ago
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    Does g(f(x))=x?

  2. anonymous
    • one year ago
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    probably one says multiply by 8, then add 3 the other says subtract 3, then divide by 8 so one undoes the other

  3. jim_thompson5910
    • one year ago
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    \[\Large \color{red}{f(x) = \frac{x-3}{8}}\] \[\Large g(x) = 8x+3\] \[\Large g(x) = 8(x)+3\] \[\Large g( \color{red}{f(x)}) = 8( \color{red}{f(x)})+3\] \[\Large g( \color{red}{f(x)}) = 8\left( \color{red}{\frac{x-3}{8}}\right)+3\] I'll let you simplify.

  4. anonymous
    • one year ago
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    So that is a yes?

  5. jim_thompson5910
    • one year ago
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    you tell me

  6. anonymous
    • one year ago
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    8s cancel each other out, and the the 3s do as well

  7. jim_thompson5910
    • one year ago
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    yes, \(\LARGE 8\left(\frac{x-3}{8}\right) + 3\) simplifies to x

  8. jim_thompson5910
    • one year ago
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    You'll also find that f(g(x)) = x as well. That means f(x) and g(x) are inverses of one another.

  9. anonymous
    • one year ago
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    Thanks.

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