anonymous
  • anonymous
MEDAL AND FAN!!!!! PLEASE HELP!!!!! Referring to the figure, find the area of the quadrilateral shown.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1436931454185:dw|
anonymous
  • anonymous
Would the answer be 12 in. ^2
jtvatsim
  • jtvatsim
Yes! You are correct! Actually, you can see that one corner fits perfectly into the other to make a rectangle. |dw:1436932124281:dw| The area is then given by 6in x 2in = 12 in ^2.

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anonymous
  • anonymous
|dw:1436931904321:dw|
anonymous
  • anonymous
Do you know how I can solve this?
anonymous
  • anonymous
@jtvatsim
jtvatsim
  • jtvatsim
Well, if you stare at the picture for a bit, you'll realize that you actually have two triangles. |dw:1436932291925:dw|
jtvatsim
  • jtvatsim
Do you know how to find the area of a triangle?
anonymous
  • anonymous
\[base \times height \div 2\]
anonymous
  • anonymous
@jtvatsim Would it be 7 cm x 4cm?
jtvatsim
  • jtvatsim
You are close. There are actually a lot of triangles that you could find the area of, after thinking about these these two are easier to work with... |dw:1436932671767:dw| The big triangle on the right has base 4cm and height 7cm. The big triangle on the left has base 4 cm and height 3 cm. Add these two areas together to get: 1/2(4cm)(7cm) + 1/2(4cm)(3cm) = 14cm^2 + 6cm^2 = 20cm^2.
jtvatsim
  • jtvatsim
Does that make sense? Any questions? :)
anonymous
  • anonymous
4x3=12 12/2=6
anonymous
  • anonymous
7x4=28 28/2=14 So..... the answer is 20 cm^2
jtvatsim
  • jtvatsim
That is correct!

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