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anonymous

  • one year ago

Simplify: √48

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  1. zzr0ck3r
    • one year ago
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    \(\sqrt{48} = \sqrt{16*3}=\sqrt{16}\sqrt{3}=?\)

  2. anonymous
    • one year ago
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    4 and 3

  3. zzr0ck3r
    • one year ago
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    its just \(4\sqrt{3}\) the square root of 16 is 4, but the square root of 3 is not so nice so we just write it as sqrt 3

  4. anonymous
    • one year ago
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    oooh ok. thank you. i don't understand any of this

  5. mathstudent55
    • one year ago
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    To simplify a root like this one, you need to find the greatest factor of 48 that is a perfect square. Here are some whole numbers and their squares: 0 0 1 1 2 4 3 9 4 16 5 25 6 36 Look in the second column. They are the squares of the first 7 whole numbers. One of them is the greatest factor of 48 that is a perfect square. It is 16. Now you rewrite 48 as a product of the greatest perfect square factor and another factor: \(\sqrt {48} = \sqrt { 16 \times 3} \) Next you separate the roots. The product of two roots equals the root of the product. \(= \sqrt{16} \times \sqrt 3\) Finally, you take the square root of 16: \(=4 \times \sqrt 3 = 4\sqrt 3\)

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