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anonymous
 one year ago
Use the Pythagorean Theorem to find the length of the missing side of a right triangle whose legs equal √2 and 2√15.
a right triangle with legs as 2 square root of 15 and square root of 2.
A. 64
B. 4 + 2√15
C. 8
D. None of the above
anonymous
 one year ago
Use the Pythagorean Theorem to find the length of the missing side of a right triangle whose legs equal √2 and 2√15. a right triangle with legs as 2 square root of 15 and square root of 2. A. 64 B. 4 + 2√15 C. 8 D. None of the above

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2The Pythagorean Theorem is \(a^2 + b^2 = c^2\) where a and b are the lengths of the legs, and c is the length of the hypotenuse.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Replace a and b with the given lengths of te legs and find c, the length of the hypotenuse.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436938653653:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Do you see how the given leg lengths are substituted into a and b?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Good. Now you need to square the two terms on the left side. When you square a product, you square every factor of the product. dw:1436939091163:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436939186380:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1it is good to be able to memorize the pythagorean theorem, but it will be better if you learned the concept and its geometrical underpinnings so you may be able to derive any solution to any problem that relates to it.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436940135801:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436940404114:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1** just a slight change in variables from what mathstudent55 provided you ** The Pythagorean theorem states that the longest leg or side namely hypotenuse, r, is the square root of the squared sum of the adjacent side, x, and opposite side, y. \(\huge r = \sqrt{x^2+y^2} \) The reason I use r, x and y, is because these notations carry over into analytical geometry and physics. And if you haven't already noticed, if I squared both sides of the equation it look the same as what you were provided. \(\large r^{\color{red}{2}} = (\sqrt{x^2+y^2} )\color{red}{^2} \rightarrow r^2 =x^2 + y^2\)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436941361148:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1and to just give you an idea as to the application that I am talking about http://hyperphysics.phyastr.gsu.edu/hbase/vect.html x's and y's never go away for some reason so we might as well accept and become familiar with them

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1why circle, pi and quadrants are important http://www.analyzemath.com/unitcircle/unit_circle_applet.html

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop you've lost me

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1Math is not a passive activity like what you did with mathstudent55. It requires you to actively seek out to understand patterns from simple to complex and what i just did is drew you what pythagorean theorem in its very backbone then added a few fundamental trigonometry information (and vocabulary) as you will encounter them very soon. The x, y and r are just variables and they are arbitrary chosen so they can be replaced with a, b and c respectively. As I explained, I picked those variables because they keep reappearing in other areas of mathematical and physical studies, which you will be encountering a lot. As an example, the variable r, x and y are used in a circle's standard form. \(\Longrightarrow (xh)^2 + (yk)^2 = r^2 \) http://www.mathwarehouse.com/geometry/circle/equationofacircle.php Should you ask why would you care about a circle when you're dealing with a triangle. The idea is how one concept can carry over into another as you may have already noticed that the r in a circle radius may be used as the hypotenuse of a right triangle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i gave up. i don't get this at all

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1what part don't you get? we can begin to what you know about math
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