anonymous
  • anonymous
please help, question in comments
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1436942415424:dw|
anonymous
  • anonymous
I'm dealing with rational exponents, and it's asking me to simplify this
anonymous
  • anonymous
|dw:1436942481286:dw|

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anonymous
  • anonymous
that simple? the answer is 1?
anonymous
  • anonymous
can you explain how you did it so I can try myself?
anonymous
  • anonymous
|dw:1436942663435:dw|
rishavraj
  • rishavraj
@Kaelyn78 see \[a^m \times a^n = a^{m + n} ~~~ and ~~~~(a^m)^{n} = a^{mn} \]
rishavraj
  • rishavraj
so \[a^8 \times a^6 = a^{14} ~~~and (a^{14})^{\frac{ 1 }{ 7 }} = a^{\frac{ 14 }{ 7 }}\]
anonymous
  • anonymous
so the equation simplified is \[a \frac{ 14 }{ 7 }\]
rishavraj
  • rishavraj
the equation u get is \[\frac{ a^{\frac{ 14 }{ 7 }} }{ a^2 } = \frac{ a^2 }{ a^2 } = 1\]
anonymous
  • anonymous
thanks for your help
rishavraj
  • rishavraj
u r most welcome :))
UsukiDoll
  • UsukiDoll
\[\large \frac{ a^{\frac{ 14 }{ 7 }} }{ a^2 } = \frac{ a^2 }{ a^2 } \rightarrow a^{2-2} \rightarrow a^0 = 1\] a step was skipped due to the zero exponent, our result will always be 1

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