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anonymous

  • one year ago

PLEASE HELP!! A circle has its center at (2,-4) and a radius of 6 units. what is the equation of the circle?

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  1. anonymous
    • one year ago
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    still confused

  2. anonymous
    • one year ago
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    We can use the standard form a a circle with center (h,k) \[(x-h)^2 + (y-k)^2 = r^2\]

  3. anonymous
    • one year ago
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    We are given the center in form Center = (h,k) Center = (2,-4) Radius (r)= 6

  4. anonymous
    • one year ago
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    plug in the values in the equation i provided and that is the eq of the circle described

  5. anonymous
    • one year ago
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    but what would x and y be

  6. anonymous
    • one year ago
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    or would i find that out later?

  7. anonymous
    • one year ago
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    x is your input y is your output

  8. anonymous
    • one year ago
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    plug in the integers given in to you so we could see exactly what kind of circle we are talking about

  9. anonymous
    • one year ago
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    Would the answer be (X+2)^2 + (y-4)^2=6 ?

  10. anonymous
    • one year ago
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    @Deeezzzz

  11. UsukiDoll
    • one year ago
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    \[(x-h)^2 + (y-k)^2 = r^2 \] <- this is the equation of the circle (h,k) <- center r<- radius since we have (2,-4) with a radius 6 that means that h = 2, k = -2, and r =6 . Just plug those values into the formula

  12. anonymous
    • one year ago
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    So it would be (x-2)^2 + (y+4)^2=6^2.... Right? @Usukidoll @Deeezzzz

  13. UsukiDoll
    • one year ago
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    that's close. you just have to expand on the 6^2 part 6 x6 =? otherwise the equation is correct.

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