anonymous
  • anonymous
PLEASE HELP!! A circle has its center at (2,-4) and a radius of 6 units. what is the equation of the circle?
Geometry
katieb
  • katieb
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anonymous
  • anonymous
still confused
anonymous
  • anonymous
We can use the standard form a a circle with center (h,k) \[(x-h)^2 + (y-k)^2 = r^2\]
anonymous
  • anonymous
We are given the center in form Center = (h,k) Center = (2,-4) Radius (r)= 6

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anonymous
  • anonymous
plug in the values in the equation i provided and that is the eq of the circle described
anonymous
  • anonymous
but what would x and y be
anonymous
  • anonymous
or would i find that out later?
anonymous
  • anonymous
x is your input y is your output
anonymous
  • anonymous
plug in the integers given in to you so we could see exactly what kind of circle we are talking about
anonymous
  • anonymous
Would the answer be (X+2)^2 + (y-4)^2=6 ?
anonymous
  • anonymous
UsukiDoll
  • UsukiDoll
\[(x-h)^2 + (y-k)^2 = r^2 \] <- this is the equation of the circle (h,k) <- center r<- radius since we have (2,-4) with a radius 6 that means that h = 2, k = -2, and r =6 . Just plug those values into the formula
anonymous
  • anonymous
So it would be (x-2)^2 + (y+4)^2=6^2.... Right? @Usukidoll @Deeezzzz
UsukiDoll
  • UsukiDoll
that's close. you just have to expand on the 6^2 part 6 x6 =? otherwise the equation is correct.

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