## anonymous one year ago [Challenge!] Give me 2 "hard" factoring polynomial equation. If I can't solve it before 5 minutes, I will be your fan. :)

1. UsukiDoll

$12x^2+10x-16$ $9999x^2+9000x-4500$ no calculators.... no online materials... all by using the quadratic formula and the discriminant formula. Have fun :)

2. welshfella

try x^4 - 2x^3 - 20x^2 - 8x - 96

3. welshfella

Hint :- factor 96

4. UsukiDoll

awww naw... we have to make it challenging and fun though ;)

5. anonymous

(x+4) (x-6) (x+2) (x-2)

6. welshfella

no cant be right because the numbers multiply out to +96

7. UsukiDoll

did you do that on your own??? xS looks wolframish

8. welshfella

this is not easy

9. anonymous

Yup..I used Synthetic Division.....

10. welshfella

(x + 4) is a factor

11. anonymous

What is the right answer then?

12. welshfella

(x^2 + 4)(x+4)(x-6)

13. anonymous

OH fudge....I factored (x^2 + 4) thinking it was (x^2-4) /facepalm Thanks anyway.

14. UsukiDoll

he was close though

15. welshfella

yes good effort

16. UsukiDoll

wanna try mine lol?

17. welshfella

I dont think yours will factor

18. UsukiDoll

how can you tell? :P

19. anonymous

I'm having a hard time in your problem xD Can you show me a step by step solution so that I could analyze it thoroughly?

20. UsukiDoll

I'm not going through that D:

21. welshfella

you'll need to use quadratic formula i think

22. UsukiDoll

oh yeah... I gave the two formulas to use XDDDDDDDDDDDD

23. UsukiDoll

discriminant formula and quadratic formula. first formula is awesome.. because you already have the b^2-4ac part

24. UsukiDoll

then when you use quadratic formula, you find the roots ... and write in factor form, so in the end you did factor... just in extra steps :P

25. anonymous

@UsukiDoll, regarding your first equation, this is my answer. $(x-8) (x+\frac{ 17 }{ x-8})$

26. UsukiDoll

oh my not even close...

27. anonymous

What?! Can you please give me the answer? Just the final no need for solution. I will try to make a solution for that final answer.