anonymous
  • anonymous
i have a question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
http://gyazo.com/b99f8d636b9355b7f990f7bead1d297f
anonymous
  • anonymous
@UsukiDoll @phi @welshfella
Vocaloid
  • Vocaloid
hint: A^B * A^C = A^(B+C)

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Vocaloid
  • Vocaloid
(add the exponents, keep the base)
UsukiDoll
  • UsukiDoll
The second one seems easier ... @Vocaloid explained it well :)
anonymous
  • anonymous
i did it think its a
Vocaloid
  • Vocaloid
another hint for the first question: A^B/A^C = A^(B-C)
anonymous
  • anonymous
i really dont know what that means at all
Vocaloid
  • Vocaloid
|dw:1436966626304:dw| simplify all your answer choices and see which one matches the question
phi
  • phi
remember that \( 9^2 \) means \( 9 \cdot 9\) and \(9^6 \) means \( 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9\) and when you multiply them you get \( 9 \cdot 9 \cdot 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9\) and you can use the "short way" by writing 9 with what as the little number in the upper right ? (to find the number, count the number of nines)
anonymous
  • anonymous
im not getting anything that's the answer
anonymous
  • anonymous
the first one give me=56 second=4 third=20 fourth=0
phi
  • phi
Do you know how to write \[ 9 \cdot 9 \cdot 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9 \] using 9 with a little number in the upper right ?
anonymous
  • anonymous
so those are the answers you get to choose from right
anonymous
  • anonymous
you know 56 4 20 0
phi
  • phi
to answer this question, you need to learn what the exponent (little number in the upper right) means examples: \[ 9^1 = 9 \\ 9^2 = 9 \cdot 9 \\ 9^3= 9 \cdot 9 \cdot 9 \] do you get that idea ? the little number tells you how many times 9 is multiplied by itself
anonymous
  • anonymous
right exactly
anonymous
  • anonymous
yes I did it
phi
  • phi
they start with \[ 9^2 \cdot 9^6 \] if we change to the "long way" to write that, it is \[ 9 \cdot 9 \ \cdot \ 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9 \]
phi
  • phi
now change the "long way" to the short way. Can you do that for \[ 9 \cdot 9 \cdot 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9 \] ?
anonymous
  • anonymous
yes
Astrophysics
  • Astrophysics
\[\huge x^n \times x^m \implies x^{n+m}\] \[\huge \frac{ x^n }{ x^m } = x^{n-m}\] I think that's more clear now.
anonymous
  • anonymous
not really am I right its a
Astrophysics
  • Astrophysics
For example \[\huge 5^6 \times 5^9 \implies 5^{6+9} = 5^{14}\]
anonymous
  • anonymous
oj thx
Astrophysics
  • Astrophysics
Np

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