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anonymous
 one year ago
Factor: x^28x+17
anonymous
 one year ago
Factor: x^28x+17

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is my answer right, \[(x8)(x+\frac{ 17 }{ x8 })\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2there's a prime number ... so I highly doubt we can factor without the quadratic formula. that's one strange root...since it's supposed to be all numbers

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.2solve the equation u got and see it matches with the equation u got

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2are you aware of the discriminant formula \[b^24ac\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I guess so...that's the formula for checking perfect trinomials right?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2perfect square numbers

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.2thts the formula to get the value of x ,,..u can say

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Going back, is (x−8)(x+17/x−8) right?

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.2@JustinSpeedster r u only askd to factorize it or get the values of x???

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2probably to factor, but how? since 17 is a prime. The only combinations are 1 x 17 17 x 1

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.2yeah its cool thennn.... by the way u got options???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got no options.... sadly.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[(8)^24(1)(17) \] solve this first. do you have a perfect square ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's obviously not a perfect square.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But if we were to solve this: \[(x+8) (x+\frac{ 17 }{ x+8 }) = x^2 +8x+17\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[6468 = 4 \] oh nice... we're going to have some imaginary i thing going on .

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2both of those aren't the right roots.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2because roots are all numbers. You can't have variables in them

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2this equation has complex roots in them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x+8 distributed to x = x^2 + 8x x+8 distrubted to x+17/x+8 leaves = 17

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How? What's wrong in that "sense"?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2you have to use the quadratic formula... wow I keep on typing that you can't have variables in the roots

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436966735517:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I was asked not to use the quadratic formula.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2dw:1436966762024:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2well you have to use the quadratic formula.. there I found the roots dw:1436966793975:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2missed a sign (x(4+i))(x(4i)) the roots are x = 4+i and x = 4i respectfully right @rishavraj

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2use discriminant formula first then quadratic formula to get the roots finally put it in factorized form ..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2thought so... thanks for verification @rishavraj

rishavraj
 one year ago
Best ResponseYou've already chosen the best response.2u r most welcome :)))
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