Factor: x^2-8x+17

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Factor: x^2-8x+17

Mathematics
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Is my answer right, \[(x-8)(x+\frac{ 17 }{ x-8 })\]
there's a prime number ... so I highly doubt we can factor without the quadratic formula. that's one strange root...since it's supposed to be all numbers
solve the equation u got and see it matches with the equation u got

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Other answers:

are you aware of the discriminant formula \[b^2-4ac\]
I guess so...that's the formula for checking perfect trinomials right?
perfect square numbers
thts the formula to get the value of x ,,..u can say
Going back, is (x−8)(x+17/x−8) right?
a = 1 b = -8 c=17
@JustinSpeedster r u only askd to factorize it or get the values of x???
Factorize only.
probably to factor, but how? since 17 is a prime. The only combinations are 1 x 17 17 x 1
yeah its cool thennn.... by the way u got options???
I got no options.... sadly.
\[(-8)^2-4(1)(17) \] solve this first. do you have a perfect square ?
It's obviously not a perfect square.
But if we were to solve this: \[(x+8) (x+\frac{ 17 }{ x+8 }) = x^2 +8x+17\]
\[64-68 = -4 \] oh nice... we're going to have some imaginary i thing going on .
both of those aren't the right roots.
because roots are all numbers. You can't have variables in them
this equation has complex roots in them
x+8 distributed to x = x^2 + 8x x+8 distrubted to x+17/x+8 leaves = 17
all wrong
How? What's wrong in that "sense"?
you have to use the quadratic formula... wow I keep on typing that you can't have variables in the roots
|dw:1436966735517:dw|
But I was asked not to use the quadratic formula.
|dw:1436966762024:dw|
well you have to use the quadratic formula.. there I found the roots |dw:1436966793975:dw|
(x(4+i))(x-(4-i))
I don't get it. >.<
missed a sign (x-(4+i))(x-(4-i)) the roots are x = 4+i and x = 4-i respectfully right @rishavraj
use discriminant formula first then quadratic formula to get the roots finally put it in factorized form ..
@UsukiDoll yup :)))
thought so... thanks for verification @rishavraj
u r most welcome :)))

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