## anonymous one year ago In the American engineering system of units, the viscosity can gave the units of (lbf)(hr)/(ft^2), while in the handbook the units are (g)/(cm)(s). Convert a viscosity of 20.0 (g)/(m)(s) to the given American Engineering units?

1. welshfella

1 gram = 0.0022046 lbs 1m = 39.37 ins

2. welshfella

1 m = 3.28083 ft

3. Empty

You can figure out any conversion factor this way, for instance: $1 \text{ hour} = 60 \text{ min}$ So if you want to convert hours to minutes, like $120 \text{ minutes}$ you want to divide out the minutes, so we take our first equation and divide both sides by minutes to get: $\frac{1 \text{ hour}}{60 \text{ minutes} }=1$ See, we can multiply anything by 1 and it doesn't change it, and this thing on the left is equal to 1! $120 \text{ minutes}*1 =120 \text{ minutes}*\frac{1 \text{ hour}}{60 \text{ minutes} } = 2 \text{ hours}$ The minutes divide out just like anything divided by itself is also 1. $\frac{7}{7}=1$ $\frac{minutes}{minutes}=1$ $\frac{elephants}{elephants}=1$

4. anonymous

$\frac{ 20g }{ (m)(s) } \times \frac{ 0.0022046lbs}{ 1g } \times \frac{ 1m }{ 3.28083 ft. } \times \frac{ 60s }{ 1 \min.} \times \frac{ 60 mins.}{ 1 hr }$

5. anonymous

is it correct? :)

6. anonymous

how can convert it into $ft^2$ for ft? if the given length is m not$m^2$

7. anonymous

@Empty

8. anonymous

and how can i put hr into the numerator?

9. anonymous

can you help me @ganeshie8 and @iGreen ? :)

10. welshfella

have another look at your question - you have ft^2 in american system but m in the metric - is this correct?

11. welshfella

looks like thers a typo somewhere

12. anonymous