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anonymous

  • one year ago

In the American engineering system of units, the viscosity can gave the units of (lbf)(hr)/(ft^2), while in the handbook the units are (g)/(cm)(s). Convert a viscosity of 20.0 (g)/(m)(s) to the given American Engineering units?

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  1. welshfella
    • one year ago
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    1 gram = 0.0022046 lbs 1m = 39.37 ins

  2. welshfella
    • one year ago
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    1 m = 3.28083 ft

  3. Empty
    • one year ago
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    You can figure out any conversion factor this way, for instance: \[1 \text{ hour} = 60 \text{ min}\] So if you want to convert hours to minutes, like \[120 \text{ minutes}\] you want to divide out the minutes, so we take our first equation and divide both sides by minutes to get: \[\frac{1 \text{ hour}}{60 \text{ minutes} }=1\] See, we can multiply anything by 1 and it doesn't change it, and this thing on the left is equal to 1! \[120 \text{ minutes}*1 =120 \text{ minutes}*\frac{1 \text{ hour}}{60 \text{ minutes} } = 2 \text{ hours} \] The minutes divide out just like anything divided by itself is also 1. \[\frac{7}{7}=1\] \[\frac{minutes}{minutes}=1\] \[\frac{elephants}{elephants}=1\]

  4. anonymous
    • one year ago
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    \[\frac{ 20g }{ (m)(s) } \times \frac{ 0.0022046lbs}{ 1g } \times \frac{ 1m }{ 3.28083 ft. } \times \frac{ 60s }{ 1 \min.} \times \frac{ 60 mins.}{ 1 hr }\]

  5. anonymous
    • one year ago
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    is it correct? :)

  6. anonymous
    • one year ago
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    how can convert it into \[ft^2\] for ft? if the given length is m not\[m^2\]

  7. anonymous
    • one year ago
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    @Empty

  8. anonymous
    • one year ago
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    and how can i put hr into the numerator?

  9. anonymous
    • one year ago
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    can you help me @ganeshie8 and @iGreen ? :)

  10. welshfella
    • one year ago
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    have another look at your question - you have ft^2 in american system but m in the metric - is this correct?

  11. welshfella
    • one year ago
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    looks like thers a typo somewhere

  12. anonymous
    • one year ago
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    yeah :(, i'll just ask my professor about this one. Thank you so much :)

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