anonymous
  • anonymous
GIVE MEDAL!! In right ∆ABC, m B = 90°, m C = 40°, and BC = 10. What are the other two side lengths of the triangle? AC = 13.1, AB = 8.4 AC = 18.7, AB = 15.8 AC = 14.3, AB = 10.2 AC = 15.6, AB = 11.9
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
iGreen
  • iGreen
We can use Sine, Cosine, and Tangent to find the remaining sides..
iGreen
  • iGreen
|dw:1436967646848:dw|
iGreen
  • iGreen
\(\sf Sine=\dfrac{Opposite}{Hypotenuse}\) \(\sf Cosine=\dfrac{Adjacent}{Hypotenuse}\) \(\sf Tangent = \dfrac{Opposite}{Adjacent}\) Here, we are given the adjacent side, and we want to find the opposite and the hypotenuse.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

iGreen
  • iGreen
Hehe, it would be if you got it yourself :P
anonymous
  • anonymous
o..k
anonymous
  • anonymous
umm..
iGreen
  • iGreen
|dw:1436968060414:dw|
iGreen
  • iGreen
So to find the hypotenuse, we can use cosine. \(\sf Cosine=\dfrac{Adjacent}{Hypotenuse}\) Plug in what we know: \(\sf cos(90^o) = \dfrac{10}{x}\)
iGreen
  • iGreen
Hmm..I think that's right..I'm not sure about which angle to use..I haven't done this in a while..
anonymous
  • anonymous
its ok
iGreen
  • iGreen
Okay, 90 degrees is wrong..
iGreen
  • iGreen
Hold on a minute
anonymous
  • anonymous
k
iGreen
  • iGreen
Okay, I think we use 40 degrees..
iGreen
  • iGreen
So: \(\sf cos(40^o) = \dfrac{10}{x}\) Type in \(\sf cos(40^o)\) into your calculator, tell me what you get.
anonymous
  • anonymous
i dont have a scientific one ..its ok ill guess but thx for help ill give tht medal :)
iGreen
  • iGreen
You can use google, just type in "cos 40 degrees"
anonymous
  • anonymous
kk
anonymous
  • anonymous
a big decimal so ill put 0.766
iGreen
  • iGreen
Yep, so we have: \(\sf 0.766 = \dfrac{10}{x}\) Solve for 'x'
anonymous
  • anonymous
so i times the decimal and 10?
anonymous
  • anonymous
or divide
iGreen
  • iGreen
Well, you can switch 'x' and 0.766 around. \(\sf x = \dfrac{10}{0.766}\) So just divide
anonymous
  • anonymous
13.1?
anonymous
  • anonymous
it was a big decimal so i round it and got tht
iGreen
  • iGreen
Sorry, my internet just went out for a few seconds there.
iGreen
  • iGreen
Yep, 13.1 is corret.
iGreen
  • iGreen
correct*
iGreen
  • iGreen
That's our hypotenuse.
anonymous
  • anonymous
its a!!!
iGreen
  • iGreen
Yes, I think that's correct.
anonymous
  • anonymous
thx for the help :)
iGreen
  • iGreen
Np

Looking for something else?

Not the answer you are looking for? Search for more explanations.