anonymous
  • anonymous
A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
dude i missed you!!! @DaBest21
anonymous
  • anonymous
there are 4/12 boys and 8/12 girls so lets say they pick girls first since they picked her she cant be picked again so now there is 11 to choose from instead of 12 so to find the probability do 4/11*8/12 and cross multiply the 4 (from 4/11) by the 8 (from 8/12) so 4*8 and do 11 (from 4/11) times 12(from 8/12) and put the answer to 4*8 on top of the fraction and the answer to 11*12 on the bottom
anonymous
  • anonymous
so what is 4*8 @thisotherliz

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anonymous
  • anonymous
32
anonymous
  • anonymous
now what is 11*12
anonymous
  • anonymous
132
anonymous
  • anonymous
yes so make the fraction 32/132 which shows the probability of 1 boy and one girl being picked which can be simplified to 8/33
anonymous
  • anonymous
dont forget to medal and mention me if u need more help p.s. it might be easier to send me a message if u need help so i can respond when helping others
anonymous
  • anonymous
the choices are 2/11 1/6 2/33 and 16/33
anonymous
  • anonymous
@DaBest21
anonymous
  • anonymous
one sec
anonymous
  • anonymous
okay
anonymous
  • anonymous
here 16/33 because there are 28 g/g pairs, 6 b/b pairs, and 32 g/b pairs. In total 66 pairs, and of those pairs 32/66 are 1 girl and 1 boy, reduced is 16/33.
anonymous
  • anonymous
let me double check @thisotherliz
anonymous
  • anonymous
oh okay thank you so much

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