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anonymous

  • one year ago

A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?

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  1. anonymous
    • one year ago
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    dude i missed you!!! @DaBest21

  2. anonymous
    • one year ago
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    there are 4/12 boys and 8/12 girls so lets say they pick girls first since they picked her she cant be picked again so now there is 11 to choose from instead of 12 so to find the probability do 4/11*8/12 and cross multiply the 4 (from 4/11) by the 8 (from 8/12) so 4*8 and do 11 (from 4/11) times 12(from 8/12) and put the answer to 4*8 on top of the fraction and the answer to 11*12 on the bottom

  3. anonymous
    • one year ago
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    so what is 4*8 @thisotherliz

  4. anonymous
    • one year ago
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    32

  5. anonymous
    • one year ago
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    now what is 11*12

  6. anonymous
    • one year ago
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    132

  7. anonymous
    • one year ago
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    yes so make the fraction 32/132 which shows the probability of 1 boy and one girl being picked which can be simplified to 8/33

  8. anonymous
    • one year ago
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    dont forget to medal and mention me if u need more help p.s. it might be easier to send me a message if u need help so i can respond when helping others

  9. anonymous
    • one year ago
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    the choices are 2/11 1/6 2/33 and 16/33

  10. anonymous
    • one year ago
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    @DaBest21

  11. anonymous
    • one year ago
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    one sec

  12. anonymous
    • one year ago
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    okay

  13. anonymous
    • one year ago
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    here 16/33 because there are 28 g/g pairs, 6 b/b pairs, and 32 g/b pairs. In total 66 pairs, and of those pairs 32/66 are 1 girl and 1 boy, reduced is 16/33.

  14. anonymous
    • one year ago
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    let me double check @thisotherliz

  15. anonymous
    • one year ago
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    oh okay thank you so much

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