A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?
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there are 4/12 boys and 8/12 girls so lets say they pick girls first since they picked her she cant be picked again so now there is 11 to choose from instead of 12 so to find the probability do 4/11*8/12 and cross multiply the 4 (from 4/11) by the 8 (from 8/12) so 4*8 and do 11 (from 4/11) times 12(from 8/12) and put the answer to 4*8 on top of the fraction and the answer to 11*12 on the bottom