Barrelracer17
  • Barrelracer17
in major need of help question in comments
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Barrelracer17
  • Barrelracer17
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Barrelracer17
  • Barrelracer17
this is for my summer school exam and i took notes but they are not helping
Michele_Laino
  • Michele_Laino
I think it is the segment GH, since the segment GH has two points in common with the circumference, furthermore its length is less than the length of the diameter AC

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Barrelracer17
  • Barrelracer17
thank you soooo much
Michele_Laino
  • Michele_Laino
thanks!! :)
Barrelracer17
  • Barrelracer17
this one?
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Barrelracer17
  • Barrelracer17
Barrelracer17
  • Barrelracer17
anonymous
  • anonymous
I'm not good at geometry at all :/ Sorry!
Barrelracer17
  • Barrelracer17
okay and its okay
Michele_Laino
  • Michele_Laino
As I can read from your drawing, I think taht: \[\angle ABC = 116^\circ \]
Michele_Laino
  • Michele_Laino
that*
Michele_Laino
  • Michele_Laino
it is another way to indicate the measure of an angle, namely: \[\Large m\widehat {ABC} = \angle ABC = 116^\circ \]
Barrelracer17
  • Barrelracer17
how do i do find out what the answer is so i can stop bothering you guys :/
Michele_Laino
  • Michele_Laino
you have to read some textbooks of geometry, since the symbols used in a textbook depends on the author of that textbook
Barrelracer17
  • Barrelracer17
oh i may need your help again
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Barrelracer17
  • Barrelracer17
Barrelracer17
  • Barrelracer17
@.Gjallarhorn.

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