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imqwerty
 one year ago
help
imqwerty
 one year ago
help

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imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1if the sum of 2 opposite sides and a diagonal of a quadrilateral is 20 and the area is 50cm^2 then find the length of other diagonal

freckles
 one year ago
Best ResponseYou've already chosen the best response.1Is this a for fun question?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1Nope :) i don't knw the answer too

freckles
 one year ago
Best ResponseYou've already chosen the best response.1Oh okay. lol Is it okay I just share some of my thoughts? I don't know the answer or yet how to get the answer.

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1I know that this question is related to the chapter solutions of triangles

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.1And i've got 1 more difficult question

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436981758315:dw like I know the area of this is \[A=\frac{1}{2}d_1(p_2+p_1)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1though we could also look at the area in terms of the other diagonal

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436981915339:dw and we could say the area of that same quadrilateral is \[A=\frac{1}{2}d_2(p_3+p_4)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1now I guess we can make the assumption that they are talking about \[DC+AB+d_1=20 \\ \text{ and we have both } 100=d_1(p_1+p_2) \text{ and } 100=d_2(p_3+p_4)\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.1but we still have a lot of unknowns

freckles
 one year ago
Best ResponseYou've already chosen the best response.1or maybe they are known just I don't know how to know them :p

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436983573101:dw

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.1\(\large \color{black}{\begin{align} &a+c+e=20,\hspace{.33em}\\~\\ &e>a,e>b,e>c,e>d,\hspace{.33em}\\~\\ &f>a,f>b,f>c,f>d,\hspace{.33em}\\~\\ &\frac{\sqrt{(a+d+e)(a+de)(a+ed)(d+ea)}}{4}+\hspace{.33em}\\~\\ &\frac{\sqrt{(b+c+e)(b+ce)(b+ec)(c+eb)}}{4}=50\hspace{.33em}\\~\\~\\~\\~\\ &\frac{\sqrt{(d+c+f)(c+df)(d+fc)(c+fd)}}{4}+\hspace{.33em}\\~\\ &\frac{\sqrt{(b+a+f)(b+af)(a+fb)(f+ba)}}{4}=50\hspace{.33em}\\~\\ \end{align}}\) some might be useful relations.

freckles
 one year ago
Best ResponseYou've already chosen the best response.1@dan815 do you know how to do this one?

dan815
 one year ago
Best ResponseYou've already chosen the best response.0ah we gotta consider heights separetly this only onle true when a and b are parallel

freckles
 one year ago
Best ResponseYou've already chosen the best response.1if it was cyclic quadrilateral I wonder if it would be easier

freckles
 one year ago
Best ResponseYou've already chosen the best response.1dw:1437016332900:dw this probably wouldn't even help

freckles
 one year ago
Best ResponseYou've already chosen the best response.1like that is only if the quadrilateral is a cyclic
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