anonymous
  • anonymous
WIL GIVE MEDAL! HELP Quadrilateral ABCD has coordinates A (3, -5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a (4 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
rectangle, because opposite sides are congruent and adjacent sides are perpendicular square, because all four sides are congruent and adjacent sides are perpendicular parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular rhombus, because all four sides are congruent and adjacent sides are not perpendicular
anonymous
  • anonymous
@princeharryyy
princeharryyy
  • princeharryyy
Solution 1>> graph it. Solution 2>> find the distance between the points. little busy :)) try them u'll get answer

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anonymous
  • anonymous
oksy can you help me with one more please?@princeharryyy
anonymous
  • anonymous
@eninone can you help me with another one?
anonymous
  • anonymous
@seth23 whynot, what's problem? post it.
anonymous
  • anonymous
Find the midpoint of diagonal BD.https://adomvirtual.brainhoney.com/Resource/27440840,0/Assets/74658_53c6c673/0601_g1_q1.jpg
anonymous
  • anonymous
@eninone
anonymous
  • anonymous
(1, 3.5) (1.5, 4) (2, 3.5) (2, 4)
anonymous
  • anonymous
\[cordinate \ of \ point \ B \ are \ (0,6) \ and \ point \ D\ are\ (3,2)\\ now \ using\ distance\ formula\ btw \ B \ and \ D\\ BD=|\sqrt{(0-3)^2+(6-2)^2}|\\ \implies \ BD= |\sqrt{3^2+4^2}|\\BD=|\sqrt{9+16}|\\BD=|\sqrt{25}|\\BD=5\ unit\\ \let \ \mid \ points\ of \ BD \ be\ (x,y)\\ then\ x=\frac{ 0+3 }{ 2}= \frac{ 3 }{ 2 }=1.5\\ y= \frac{ (6+2) }{ 2}=\frac{ 8 }{ 2 }=4\\ \therefore\ midpoints\ of\ BD \ are \ (1.5\,\ 4)\ Q.E.D.\\\\ -----LOGICFALL\ Co.-----\]
anonymous
  • anonymous
oh! no, no need to find distance BD, mistakely done! Just see the last part. @seth23 ANS= (1.5, 4)
princeharryyy
  • princeharryyy
Sorry ! I was on call.

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