## anonymous one year ago WIL GIVE MEDAL! HELP Quadrilateral ABCD has coordinates A (3, -5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a (4 points)

1. anonymous

rectangle, because opposite sides are congruent and adjacent sides are perpendicular square, because all four sides are congruent and adjacent sides are perpendicular parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular rhombus, because all four sides are congruent and adjacent sides are not perpendicular

2. anonymous

@princeharryyy

3. princeharryyy

Solution 1>> graph it. Solution 2>> find the distance between the points. little busy :)) try them u'll get answer

4. anonymous

oksy can you help me with one more please?@princeharryyy

5. anonymous

@eninone can you help me with another one?

6. anonymous

@seth23 whynot, what's problem? post it.

7. anonymous

Find the midpoint of diagonal BD. https://adomvirtual.brainhoney.com/Resource/27440840,0/Assets/74658_53c6c673/0601_g1_q1.jpg

8. anonymous

@eninone

9. anonymous

(1, 3.5) (1.5, 4) (2, 3.5) (2, 4)

10. anonymous

$cordinate \ of \ point \ B \ are \ (0,6) \ and \ point \ D\ are\ (3,2)\\ now \ using\ distance\ formula\ btw \ B \ and \ D\\ BD=|\sqrt{(0-3)^2+(6-2)^2}|\\ \implies \ BD= |\sqrt{3^2+4^2}|\\BD=|\sqrt{9+16}|\\BD=|\sqrt{25}|\\BD=5\ unit\\ \let \ \mid \ points\ of \ BD \ be\ (x,y)\\ then\ x=\frac{ 0+3 }{ 2}= \frac{ 3 }{ 2 }=1.5\\ y= \frac{ (6+2) }{ 2}=\frac{ 8 }{ 2 }=4\\ \therefore\ midpoints\ of\ BD \ are \ (1.5\,\ 4)\ Q.E.D.\\\\ -----LOGICFALL\ Co.-----$

11. anonymous

oh! no, no need to find distance BD, mistakely done! Just see the last part. @seth23 ANS= (1.5, 4)

12. princeharryyy

Sorry ! I was on call.