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anonymous

  • one year ago

WIL GIVE MEDAL! HELP Quadrilateral ABCD has coordinates A (3, -5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a (4 points)

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  1. anonymous
    • one year ago
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    rectangle, because opposite sides are congruent and adjacent sides are perpendicular square, because all four sides are congruent and adjacent sides are perpendicular parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular rhombus, because all four sides are congruent and adjacent sides are not perpendicular

  2. anonymous
    • one year ago
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    @princeharryyy

  3. princeharryyy
    • one year ago
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    Solution 1>> graph it. Solution 2>> find the distance between the points. little busy :)) try them u'll get answer

  4. anonymous
    • one year ago
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    oksy can you help me with one more please?@princeharryyy

  5. anonymous
    • one year ago
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    @eninone can you help me with another one?

  6. anonymous
    • one year ago
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    @seth23 whynot, what's problem? post it.

  7. anonymous
    • one year ago
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    Find the midpoint of diagonal BD. https://adomvirtual.brainhoney.com/Resource/27440840,0/Assets/74658_53c6c673/0601_g1_q1.jpg

  8. anonymous
    • one year ago
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    @eninone

  9. anonymous
    • one year ago
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    (1, 3.5) (1.5, 4) (2, 3.5) (2, 4)

  10. anonymous
    • one year ago
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    \[cordinate \ of \ point \ B \ are \ (0,6) \ and \ point \ D\ are\ (3,2)\\ now \ using\ distance\ formula\ btw \ B \ and \ D\\ BD=|\sqrt{(0-3)^2+(6-2)^2}|\\ \implies \ BD= |\sqrt{3^2+4^2}|\\BD=|\sqrt{9+16}|\\BD=|\sqrt{25}|\\BD=5\ unit\\ \let \ \mid \ points\ of \ BD \ be\ (x,y)\\ then\ x=\frac{ 0+3 }{ 2}= \frac{ 3 }{ 2 }=1.5\\ y= \frac{ (6+2) }{ 2}=\frac{ 8 }{ 2 }=4\\ \therefore\ midpoints\ of\ BD \ are \ (1.5\,\ 4)\ Q.E.D.\\\\ -----LOGICFALL\ Co.-----\]

  11. anonymous
    • one year ago
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    oh! no, no need to find distance BD, mistakely done! Just see the last part. @seth23 ANS= (1.5, 4)

  12. princeharryyy
    • one year ago
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    Sorry ! I was on call.

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