anonymous
  • anonymous
What is the equation of a line passing through (-6, 5) and having a slope of 1/3?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
y=1/3x+5
anonymous
  • anonymous
that's not one of my listed answers would it be y=1/3x+7
anonymous
  • anonymous
First of all, remember what the equation of a line is: y = mx+b Where: m is the slope, and b is the y-intercept

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anonymous
  • anonymous
let me see all the listed answers
anonymous
  • anonymous
The equation of the line that passes through the point (-6,5) with a slope of 1/3 is y=1/3x+7
anonymous
  • anonymous
so far so good @pinkbubbles
anonymous
  • anonymous
but where did the seven come from?
anonymous
  • anonymous
(-6,5). y=mx+b or 5=1/3 × -6+b, or solving for b: b=5-(1/3)(-6). b=7
anonymous
  • anonymous
anonymous
  • anonymous
A.y=1/3x-23/3 B.y=1/3x-3 C.y=1/3x+7 D.y=3x+7
anonymous
  • anonymous
The equation of the line that passes through the point (-6,5) with a slope of 1/3 is y=1/3x+7
anonymous
  • anonymous
ok thank u :D
anonymous
  • anonymous
Welcome! @sherlocked1270 :)

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