Equation A: 3c = d − 8 Equation B: c = 4d + 8 Which of the following steps should be performed to eliminate variable d first? Multiply equation A by −4. Multiply equation B by 3. Multiply equation A by 3. Multiply equation B by 4.

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Equation A: 3c = d − 8 Equation B: c = 4d + 8 Which of the following steps should be performed to eliminate variable d first? Multiply equation A by −4. Multiply equation B by 3. Multiply equation A by 3. Multiply equation B by 4.

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Step 1: 2(y + 4) = 4y Step 2: 2y + 6 = 4y Step 3: 2y = 6 Step 4: y = 3 Which of the following explains how to correct Step 2 and shows the correct value of y? The equation should be y + 4 = 4y after division by 2; y = 5 The equation should be y + 4 = 4y after division by 2; y = 2 2 should be distributed as 2y + 8; y = 4 2 should be distributed as 2y + 8; y = 2 @eninone

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step 2: 2y+8= 4y correct?
yes
@hayespurdy 2 should be distributed as 2y+8=4y, y=4. this is correct. as put y=4 in lhs and rhs. you get lhs=rhs. not in any othr case.

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