• anonymous
A reaction A+B+C->D has the following differential rate law: rate=k[A][B]^2. a)if the concentration of A is tripled, what happens to the rate? b) if the concentration of A is doubled and the concentration of C is halved, what happens to the rate? Thank you
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • jamiebookeater
I got my questions answered at in under 10 minutes. Go to now for free help!
  • Photon336
This reaction the rare is r = k[A][B]^2 This means that the reaction is second order with respect to B and first order with respect to A. Overall we just count the exponents to figure out overall reaction rate 1+2 = 3. This is a third order reaction. If we triple the [a] --> [3a] and keep the concentration of B constant. Then your rate should go up by a factor of 3.
  • Photon336
The [C] doesn't apply because it simply isn't in our rate law. There is no term for that in what was given in the problem so increasing the concentration of [C] wouldn't do anything. If you double [A] then you double your reaction rate goes up by a factor of 2.
  • Photon336
Rate laws are experimentally determined, by keeping the concentration of one of your substances constant while studying the change in concentration of the other.

Looking for something else?

Not the answer you are looking for? Search for more explanations.