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vera_ewing
 one year ago
chem
vera_ewing
 one year ago
chem

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Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Ask yourself what happens at your equivalent point? You've added equimolar quantities of acid/base hence neutralization

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do you think? do you know where is the equivalence point in the graph?

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0I'm pretty sure it's C. Is that right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think you are right, I would choose the same answer

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0That's still within the equivalence point it, says "above equivalence point" so I think it would be 12

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0You can eliminate 2 and 8 right away because one is the equivalent point where the other is past it. If you see at the equivalencen point you add equimolar quantities of acid and base so the term A/HA drops out and you are left with pH= pKA and at that flat line where 8 is you'll have the greatest resistance to change in pH.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0Sorry pH of 2 is not past but before the equivalence point.

Photon336
 one year ago
Best ResponseYou've already chosen the best response.0I agree with @Cuanchi
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