vera_ewing
  • vera_ewing
chem
Chemistry
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vera_ewing
  • vera_ewing
chem
Chemistry
jamiebookeater
  • jamiebookeater
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vera_ewing
  • vera_ewing
vera_ewing
  • vera_ewing
Photon336
  • Photon336
Ask yourself what happens at your equivalent point? You've added equimolar quantities of acid/base hence neutralization

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Cuanchi
  • Cuanchi
what do you think? do you know where is the equivalence point in the graph?
vera_ewing
  • vera_ewing
I'm pretty sure it's C. Is that right?
Cuanchi
  • Cuanchi
I think you are right, I would choose the same answer
vera_ewing
  • vera_ewing
Thanks! :)
Photon336
  • Photon336
That's still within the equivalence point it, says "above equivalence point" so I think it would be 12
Photon336
  • Photon336
You can eliminate 2 and 8 right away because one is the equivalent point where the other is past it. If you see at the equivalencen point you add equimolar quantities of acid and base so the term A-/HA drops out and you are left with pH= pKA and at that flat line where 8 is you'll have the greatest resistance to change in pH.
Photon336
  • Photon336
Sorry pH of 2 is not past but before the equivalence point.
Photon336
  • Photon336
I agree with @Cuanchi

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