anonymous
  • anonymous
The deflection of alpha particles in Rutherford’s gold foil experiments resulted in what change to the atomic model? The addition of energy levels and orbitals to the electron cloud The addition of a small, dense nucleus to the center of the atom The addition of wave properties to the characteristics of an electron The addition of neutrons to the nucleus of the atom
Chemistry
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katieb
  • katieb
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anonymous
  • anonymous
Which of the following pairs of elements could possibly be found in the same group on the periodic table? A is an alkali metal; B forms a 1- ion. A has two valence electrons; B forms a 2- ion. A is a noble gas; B has seven valence electrons. A forms a -3 ion; B has five valence electrons.
anonymous
  • anonymous
@Photon336
anonymous
  • anonymous
n anyone answer these please thanks

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anonymous
  • anonymous
n atom is determined to contain 17 protons, 18 electrons, and 18 neutrons. What are the mass number and charge of this atom or ion? Mass number: 36, charge: -1 Mass number: 35, charge: +1 Mass number: 35, charge: -1 Mass number: 36, charge: neutral
anonymous
  • anonymous
@Cuanchi
Photon336
  • Photon336
Addition of a small dense nucleus, he said that the atom was mostly empty space. Surrounded by electrons.
Photon336
  • Photon336
Same group would mean same number of valence electrons
anonymous
  • anonymous
so it woulod b @Photon336
anonymous
  • anonymous
oh never mind can you answer thee onther ones @Photon336
Photon336
  • Photon336
For your other question The first two don't make sense because group one and two are the alkali and alkai earth metals and have one and two valence electrons. They are reactive because of the tendency to lose those electrons so they would never have a negative ion. So the first two are out A noble gas configuration would put the element in group 8, an element with seven valence electrons would place it in group 7 alongside the halogens. If something has 5 valence electrons it can take on a charge of -3 to satisfy its octet and still be within the same group so that one to me makes the most sense.
Photon336
  • Photon336
For the Rutherford model it would be B he did not show that there are neutrons in the nucleus yet.
anonymous
  • anonymous
so it would be c for number 2
anonymous
  • anonymous
@Photon336
anonymous
  • anonymous
Which question you need help with?
Photon336
  • Photon336
For your last one, any element is defined by its atomic number # which is the number of protons. All atoms are electrically neutral # protons = # of electrons unless there's an ion. The mass number is the number of protons and neutrons. And this tells us the existence of isotopes. In this case we have 17 protons that's the atomic number. Now we have 18 electrons because there are more protons our charge is -1. Now the mass number is the number of protons and neutrons which is just 17+18 = 35
anonymous
  • anonymous
Which of the following compounds will experience hydrogen bonding? NH3 HBr C2H4 H2SO4
anonymous
  • anonymous
What coefficients can be used to balance the following equation? K2CO3 + FeCl3 yields KCl + Fe2 (CO3)3 2, 2, 4, 1 3, 2, 6, 1 1, 1, 2, 1 3, 3, 6, 1 Question 21 (Multiple Choice Worth 2 points) How is percent yield calculated? Measured mass of limiting reactant divided by the measured mass of the excess reactant given at the beginning of the reaction Measured mass of excess reactant divided by the measured mass of the limiting reactant used in the reaction Measured mass of product actually produced divided by calculated mass of product that should be produced by the given amount of reactants Calculated mass of product that should be produced by the given amount of reactants divided by the measured mass of product actually produced
anonymous
  • anonymous
@pinkbubbles @Photon336
anonymous
  • anonymous
Which of the following compounds will experience hydrogen bonding? Your answer is NH3
anonymous
  • anonymous
Can you open a new question please?
anonymous
  • anonymous
@jammy987 are you there?
anonymous
  • anonymous
yes
anonymous
  • anonymous
Can you open a new question please?

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